OWLV2 FOR MOORE/STANITSKI'S CHEMISTRY:
OWLV2 FOR MOORE/STANITSKI'S CHEMISTRY:
5th Edition
ISBN: 9781285460369
Author: STANITSKI
Publisher: Cengage Learning
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Chapter 5, Problem 43QRT

(a)

Interpretation Introduction

Interpretation:

A correct set of four quantum numbers for each electron in boron atom has to be given.

Concept Introduction:

Principal Quantum Number (n): In an atom, the electron energy mainly depends on principal quantum number.  The energy of an electron becomes lower when the value of n is smaller.  The orbital size also depends on n.  The size of orbital increases with increase in value of principal quantum number (n)

Angular Momentum Quantum Number (l): It helps to differentiate different shapes of orbitals for given n.  For a given n, there are n different shapes of orbitals are present and are denoted as l.   Angular momentum quantum number is also known as Azimuthal quantum number.  The possible values of angular momentum quantum number are between 0and(n-1).  If the n is 3, then l value is 0,1,2

Magnetic Quantum Number (ml): It helps to distinguish orbitals having various orientations in space.  Any integer between -l and +l is the probable values of magnetic quantum number.   For s subshell the l=0, then ml is zero.   For p subshell the l=1, then ml=1,0,+1

Spin Quantum Number (ms): It refers to direction of spin of an electron in an orbital.  The possible values are +12or-12.

(a)

Expert Solution
Check Mark

Explanation of Solution

The electronic configuration of boron atom is given by

    1s2 2s2 2p1

The arrangement of electrons in boron atom is

    OWLV2 FOR MOORE/STANITSKI'S CHEMISTRY:, Chapter 5, Problem 43QRT , additional homework tip  1

First electron in 1s orbital:  n=1,l=0,ml=0,andms=+12

Second electron in 2s orbital:  n=1,l=0,ml=0,andms=12

First electron in 2s orbital:  n=2,l=0,ml=0,andms=+12

Second electron in 2s orbital:  n=2,l=0,ml=0,andms=12

First electron in 2p orbital:  n=2,l=1,ml=+1,andms=+12

(b)

Interpretation Introduction

Interpretation:

A correct set of four quantum numbers for 3s electrons in magnesium atom has to be given.

Concept Introduction:

Refer to part (a)

(b)

Expert Solution
Check Mark

Explanation of Solution

The electronic configuration of magnesium atom is given by

    1s2 2s2 2p1

The arrangement of 3s electrons in magnesium atom is

    OWLV2 FOR MOORE/STANITSKI'S CHEMISTRY:, Chapter 5, Problem 43QRT , additional homework tip  2

First electron in 3s orbital:  n=3,l=0,ml=0,ands=+12

Second electron in 3s orbital:  n=3,l=0,ml=0,ands=12

(c)

Interpretation Introduction

Interpretation:

A correct set of four quantum numbers for a 3d electron in iron atom has to be given.

Concept Introduction:

Refer to part (a)

(c)

Expert Solution
Check Mark

Explanation of Solution

The electronic configuration of iron atom is given by

    1s2 2s2 2p6 3s2 3p6 4s2 3d6

The arrangement of a 3d electron in iron atom is

    OWLV2 FOR MOORE/STANITSKI'S CHEMISTRY:, Chapter 5, Problem 43QRT , additional homework tip  3

First electron in 3d orbital:  n=3,l=2,ml=+2,andms=+12

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Chapter 5 Solutions

OWLV2 FOR MOORE/STANITSKI'S CHEMISTRY:

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