Mass in grams of solute needed to prepare 0.250 L of 0.167 M should be determined. Concept introduction: The concentration of any solution means the amount of solute present in the specific volume of the solvent. Now the amount of solute present in the solution is expressed by different units like gram, gram-equivalent, gram-mole or mole etc. The amount of solvent to prepare the solution can be expressed in terms of weight or volume. The different unit of expression the concentration of a solution are- percentage strength, normality, molarity, molality, formality, gram per litter, mole fraction, parts per million etc. Molarity: In per litter (1000 mL or 1000 cc) volume of any solution the amount of solute present in gram-mole is called the molarity of the solution. It is expressed by ‘M’. Like- If in 1 L of solution 2 gm-mole of the pure is present then the strength of the solution will be 2 M. It can be expressed as-

Question

Want to see the full answer?

Answer 1

Question

Chapter 5, Problem 42P

a.

Interpretation Introduction

Interpretation:

Mass in grams of solute needed to prepare 0.250 L of 0.167 M should be determined.

Concept introduction:

The concentration of any solution means the amount of solute present in the specific volume of the solvent. Now the amount of solute present in the solution is expressed by different units like gram, gram-equivalent, gram-mole or mole etc. The amount of solvent to prepare the solution can be expressed in terms of weight or volume. The different unit of expression the concentration of a solution are- percentage strength, normality, molarity, molality, formality, gram per litter, mole fraction, parts per million etc.

Molarity: In per litter (1000 mL or 1000 cc) volume of any solution the amount of solute present in gram-mole is called the molarity of the solution. It is expressed by ‘M’. Like- If in 1 L of solution 2 gm-mole of the pure is present then the strength of the solution will be 2 M. It can be expressed as-

b.

Interpretation Introduction

Interpretation:

Mass in grams of solute needed to prepare 625 mL of 0.0200 M should be determined

Concept introduction:

The concentration of any solution means the amount of solute present in the specific volume of the solvent. Now the amount of solute present in the solution is expressed by different units like gram, gram-equivalent, gram-mole or mole etc. The amount of solvent to prepare the solution can be expressed in terms of weight or volume. The different unit of expression the concentration of a solution are- percentage strength, normality, molarity, molality, formality, gram per litter, mole fraction, parts per million etc.

Molarity: In per litter (1000 mL or 1000 cc) volume of any solution the amount of solute present in gram-mole is called the molarity of the solution. It is expressed by ‘M’. Like- If in 1 L of solution 2 gm-mole of the pure is present then the strength of the solution will be 2 M. It can be expressed as-

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. ? NH2 MgBr Will the first product that forms in this reaction create a new CC bond? ○ Yes ○ No MgBr ? Will the first product that forms in this reaction create a new CC bond? O Yes O No Click and drag to start drawing a structure. :☐ G x c olo Ar HE

Predicting As the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C - C bond as its major product: H₂N O H 1. ? 2. H3O+ If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. 0 If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. فا Explanation Check Click and drag to start drawing a structure.

Highlight the chirality (or stereogenic) center(s) in the given compound. A compound may have one or more stereogenic centers. OH OH OH OH OH OH