Ascent rate of a scuba diver Divers who ascend too quickly in the water risk decompression illness . A common recommendation for a maximum rate of ascent is 30 feet/minute with a 5-minute safety stop 15 feet below the surface of the water. Suppose that a diver ascends to the surface in 8 minutes according to the velocity function v ( t ) = { 30 if 0 ≤ t ≤ 2 0 if 2 < t ≤ 7 15 if 7 < t ≤ 8. a. Graph the velocity function v . b. Compute the area under the velocity curve. c. Interpret the physical meaning of the area under the velocity curve.
Ascent rate of a scuba diver Divers who ascend too quickly in the water risk decompression illness . A common recommendation for a maximum rate of ascent is 30 feet/minute with a 5-minute safety stop 15 feet below the surface of the water. Suppose that a diver ascends to the surface in 8 minutes according to the velocity function v ( t ) = { 30 if 0 ≤ t ≤ 2 0 if 2 < t ≤ 7 15 if 7 < t ≤ 8. a. Graph the velocity function v . b. Compute the area under the velocity curve. c. Interpret the physical meaning of the area under the velocity curve.
Solution Summary: The author illustrates how the graph of velocity function is a step function. The area under the velocity curve is calculated as follows.
Ascent rate of a scuba diver Divers who ascend too quickly in the water risk decompression illness. A common recommendation for a maximum rate of ascent is 30 feet/minute with a 5-minute safety stop 15 feet below the surface of the water. Suppose that a diver ascends to the surface in 8 minutes according to the velocity function
v
(
t
)
=
{
30
if 0
≤
t
≤
2
0
if
2
<
t
≤
7
15
if
7
<
t
≤
8.
a. Graph the velocity function v.
b. Compute the area under the velocity curve.
c. Interpret the physical meaning of the area under the velocity curve.
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