Interpretation:
It is to be explained why the reaction of one of the trimethylcyclohexanols shown with hydrogen chloride gives a single product while the other gives a mixture of two stereoisomers.
Concept introduction:
Secondary and tertiary alcohols react with hydrogen halide by an
Tertiary carbocations are stable and allow both the faces to become equivalent with respect to their surroundings. However, sterically less hindered face is favorable.
In case of alcohols, the first step in an
The alkyloxonium ion dissociates to a water molecule in the second step, and a carbocation is formed.
The third step is the reaction of a carbocation with the nucleophile. The nucleophile uses an unshared electron pair that can be used to form a covalent bond between the carbon atom of a carbocation and the halide ion.
For sterically hindered cyclohexanols, the sterically less hindered sites are favorable to form a product.
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Chapter 5 Solutions
ORGANIC CHEMISTRY (LOOSELEAF)-PACKAGE
- Part V. Draw the structure of compound tecla using the IR spectrum Cobtained from the compound in KBr pellet) and the mass spectrum as shown below. The mass spectrum of compound Tesla showed strong mt peak at 71. TRANSMITTANCE LOD Relative Intensity 100 MS-NW-1539 40 20 80 T 44 55 10 15 20 25 30 35 40 45 50 55 60 65 70 75 m/z D 4000 3000 2000 1500 1000 500 HAVENUMBERI-11arrow_forwardTechnetium is the first element in the periodic chart that does not have any stable isotopes. Technetium-99m is an especially interesting and valuable isotope as it emits a gamma ray with a half life ideally suited for medical tests. It would seem that the decay of technetium should fit the treatment above with the result In(c/c) = -kt. The table below includes data from the two sites: http://dailymed.nlm.nih.gov/dailymed/druginfo.cfm?id=7130 http://wiki.medpedia.com/Clinical: Neutrospec_(Technetium_(99m Tc)_fanolesomab). a. b. C. Graph the fraction (c/c.) on the vertical axis versus the time on the horizontal axis. Also graph In(c/c.) on the vertical axis versus time on the horizontal axis. When half of the original amount of starting material has hours fraction remaining disappeared, c/c = ½ and the equation In(c/c.) = -kt becomes In(0.5) = -kt1/2 where t₁₂ is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c.) vs t graph and…arrow_forwardPlease correct answer and don't use hand ratingarrow_forward
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- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning