Chapter 5, Problem 30QP

Interpretation Introduction

Interpretation:

The energy change in the given reaction under the given conditions is to be calculated.

Concept Introduction:

Sign of heat is positive, if heat is absorbed by the system, and negative if heat is released by the system.

Sign of work done is negative, if work is done by the system, and positive if work is done on the system.

The work done is calculated by the formula as:

$w=-P\left(V_2-V_1\right)$

Here, $w$ is the work done, $P$ is the pressure, $V_1$ is the initial volume of gas, and $V_2$ is the final volume of the gas.

The conversion of work done from $\text{mL}\cdot \text{atm}$ into $\text{kJ}$ is done as:

$1\text{L atm}=0.1013\text{kJ}$

The energy change of the system is calculated by the formula as:

$\Delta U=q+w$

Here, $\Delta U$ is the energy change, $q$ is the heat change, and $w$ is the work done of the system.