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High School Math Algebra EP ALGEBRA 2-COMMON CORE-ONLINE ACCESS

(a) To discribe : The sequence of transformation that could take the given graph to the parent function. The transformed cubic function is y = − ( x − 4 ) 2 + 4 . Given information : The parent function is y = x 2 and the graph is: Explanation : Given y = x 2 . Now, y = − x 2 { Reflect across the x − axis by multiplying with − 1. } y = − x 2 + 4 { Translate four units up by adding 4. } y = − ( x − 4 ) 2 + 4 { Translate four units right by replacing x with ( x − 4 ) . } ........ (1) Graph all the above equations using graphing calculator as below: Therefore, the transformed cubic function is y = − ( x − 4 ) 2 + 4 . (b) To identify : The zeros of the function represented in the graph. The zeros of the function represented by the given graph are x = 2 and 6 . Given information : The parent function is y = x 2 and the graph is: Explanation : The function represented in the graph is y = − ( x − 4 ) 2 + 4 and it intersects the x − axis at ( 2 , 0 ) and ( 6 , 0 ) . Therefore, the zeros of the function are x = 2 and 6 . (c) To Find : The equation represented by the graph. The function represented in the graph is y = − ( x − 4 ) 2 + 4 . Given information : The parent function is y = x 2 and the graph is: Explanation : The parent function is y = x 2 . Now, y = − x 2 { Reflect across the x − axis by multiplying with − 1. } y = − x 2 + 4 { Translate four units up by adding 4. } y = − ( x − 4 ) 2 + 4 { Translate four units right by replacing x with ( x − 4 ) . } ........ (1) The function represented in the graph is y = − ( x − 4 ) 2 + 4 . (d) To verify : The equation represented by the graph. Given information : The parent function is y = x 2 and the graph is: Proof : The function represented in the graph is y = − ( x − 4 ) 2 + 4 and its zeros are x = 2 and 6 . Check the coordinates by substituting them in y = − ( x − 4 ) 2 + 4 . For ( 2 , 0 ) y = − ( x − 4 ) 2 + 4 0 = − ( 2 − 4 ) 2 + 4 0 = − 4 + 4 0 = 0 For ( 6 , 0 ) y = − ( x − 4 ) 2 + 4 0 = − ( 6 − 4 ) 2 + 4 0 = − 4 + 4 0 = 0 Hence, proved.

(a) To discribe : The sequence of transformation that could take the given graph to the parent function. The transformed cubic function is y = − ( x − 4 ) 2 + 4 . Given information : The parent function is y = x 2 and the graph is: Explanation : Given y = x 2 . Now, y = − x 2 { Reflect across the x − axis by multiplying with − 1. } y = − x 2 + 4 { Translate four units up by adding 4. } y = − ( x − 4 ) 2 + 4 { Translate four units right by replacing x with ( x − 4 ) . } ........ (1) Graph all the above equations using graphing calculator as below: Therefore, the transformed cubic function is y = − ( x − 4 ) 2 + 4 . (b) To identify : The zeros of the function represented in the graph. The zeros of the function represented by the given graph are x = 2 and 6 . Given information : The parent function is y = x 2 and the graph is: Explanation : The function represented in the graph is y = − ( x − 4 ) 2 + 4 and it intersects the x − axis at ( 2 , 0 ) and ( 6 , 0 ) . Therefore, the zeros of the function are x = 2 and 6 . (c) To Find : The equation represented by the graph. The function represented in the graph is y = − ( x − 4 ) 2 + 4 . Given information : The parent function is y = x 2 and the graph is: Explanation : The parent function is y = x 2 . Now, y = − x 2 { Reflect across the x − axis by multiplying with − 1. } y = − x 2 + 4 { Translate four units up by adding 4. } y = − ( x − 4 ) 2 + 4 { Translate four units right by replacing x with ( x − 4 ) . } ........ (1) The function represented in the graph is y = − ( x − 4 ) 2 + 4 . (d) To verify : The equation represented by the graph. Given information : The parent function is y = x 2 and the graph is: Proof : The function represented in the graph is y = − ( x − 4 ) 2 + 4 and its zeros are x = 2 and 6 . Check the coordinates by substituting them in y = − ( x − 4 ) 2 + 4 . For ( 2 , 0 ) y = − ( x − 4 ) 2 + 4 0 = − ( 2 − 4 ) 2 + 4 0 = − 4 + 4 0 = 0 For ( 6 , 0 ) y = − ( x − 4 ) 2 + 4 0 = − ( 6 − 4 ) 2 + 4 0 = − 4 + 4 0 = 0 Hence, proved.

EP ALGEBRA 2-COMMON CORE-ONLINE ACCESS

EP ALGEBRA 2-COMMON CORE-ONLINE ACCESS

15th Edition

ISBN: 9780133318050

Author: Charles

Publisher: PH SCHOOL

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Expert Solution & Answer

Chapter 5, Problem 23CCSR

Solution

(a)

To discribe : The sequence of transformation that could take the given graph to the parent function.

The transformed cubic function is y=−(x−4)2+4 .

Given information :

The parent function is y=x2 and the graph is:

Explanation :

Given y=x2 . Now,

y=−x2 {Reflect across the x−axis by multiplying with −1.}y=−x2+4 {Translate four units up by adding 4.}y=−(x−4)2+4 {Translate four units right by replacing x with (x−4).} ........ (1)

Graph all the above equations using graphing calculator as below:

Therefore, the transformed cubic function is y=−(x−4)2+4 .

(b)

To identify : The zeros of the function represented in the graph.

The zeros of the function represented by the given graph are x=2 and 6 .

Given information :

The parent function is y=x2 and the graph is:

Explanation :

The function represented in the graph is y=−(x−4)2+4 and it intersects the x− axis at (2,0) and (6,0) .

Therefore, the zeros of the function are x=2 and 6 .

(c)

To Find : The equation represented by the graph.

The function represented in the graph is y=−(x−4)2+4 .

Given information :

The parent function is y=x2 and the graph is:

Explanation :

The parent function is y=x2 . Now,

y=−x2 {Reflect across the x−axis by multiplying with −1.}y=−x2+4 {Translate four units up by adding 4.}y=−(x−4)2+4 {Translate four units right by replacing x with (x−4).} ........ (1)

The function represented in the graph is y=−(x−4)2+4 .

(d)

To verify : The equation represented by the graph.

Given information :

The parent function is y=x2 and the graph is:

Proof :

The function represented in the graph is y=−(x−4)2+4 and its zeros are x=2 and 6 .

Check the coordinates by substituting them in y=−(x−4)2+4 .

For (2,0)

y=−(x−4)2+40=−(2−4)2+40=−4+40=0

For (6,0)

y=−(x−4)2+40=−(6−4)2+40=−4+40=0

Hence, proved.

Chapter 5, Problem 22CCSR

Chapter 6.1, Problem 1E

Chapter 5 Solutions

EP ALGEBRA 2-COMMON CORE-ONLINE ACCESS

Ch. 5.1 - Prob. 1LC Ch. 5.1 - Prob. 2LC Ch. 5.1 - Prob. 3LC Ch. 5.1 - Prob. 4LC Ch. 5.1 - Prob. 5LC Ch. 5.1 - Prob. 6LC Ch. 5.1 - Prob. 7LC Ch. 5.1 - Prob. 8PPSE Ch. 5.1 - Prob. 9PPSE Ch. 5.1 - Prob. 10PPSE

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Prob. 64PPSE Ch. 5.7 - Prob. 65PPSE Ch. 5.7 - Prob. 66PPSE Ch. 5.7 - Prob. 67PPSE Ch. 5.7 - Prob. 68PPSE Ch. 5.8 - Prob. 1LC Ch. 5.8 - Prob. 2LC Ch. 5.8 - Prob. 3LC Ch. 5.8 - Prob. 4LC Ch. 5.8 - Prob. 5LC Ch. 5.8 - Prob. 6LC Ch. 5.8 - Prob. 7LC Ch. 5.8 - Prob. 8PPSE Ch. 5.8 - Prob. 9PPSE Ch. 5.8 - Prob. 10PPSE Ch. 5.8 - Prob. 11PPSE Ch. 5.8 - Prob. 12PPSE Ch. 5.8 - Prob. 13PPSE Ch. 5.8 - Prob. 14PPSE Ch. 5.8 - Prob. 15PPSE Ch. 5.8 - Prob. 16PPSE Ch. 5.8 - Prob. 17PPSE Ch. 5.8 - Prob. 18PPSE Ch. 5.8 - Prob. 19PPSE Ch. 5.8 - Prob. 20PPSE Ch. 5.8 - Prob. 21PPSE Ch. 5.8 - Prob. 22PPSE Ch. 5.8 - Prob. 23PPSE Ch. 5.8 - Prob. 24PPSE Ch. 5.8 - Prob. 25PPSE Ch. 5.8 - Prob. 26PPSE Ch. 5.8 - Prob. 27PPSE Ch. 5.8 - Prob. 28PPSE Ch. 5.8 - Prob. 29PPSE Ch. 5.8 - Prob. 30PPSE Ch. 5.8 - Prob. 31PPSE Ch. 5.8 - Prob. 32PPSE Ch. 5.8 - Prob. 33PPSE Ch. 5.8 - Prob. 34PPSE Ch. 5.8 - Prob. 35PPSE Ch. 5.8 - Prob. 36PPSE Ch. 5.8 - Prob. 37PPSE Ch. 5.8 - Prob. 38PPSE Ch. 5.8 - Prob. 39PPSE Ch. 5.8 - Prob. 40PPSE Ch. 5.8 - Prob. 41PPSE Ch. 5.8 - Prob. 42PPSE Ch. 5.8 - Prob. 43PPSE Ch. 5.8 - Prob. 44PPSE Ch. 5.8 - Prob. 45PPSE Ch. 5.8 - Prob. 46PPSE Ch. 5.8 - Prob. 47PPSE Ch. 5.8 - Prob. 48PPSE Ch. 5.8 - Prob. 49PPSE Ch. 5.8 - Prob. 50PPSE Ch. 5.8 - Prob. 51PPSE Ch. 5.8 - Prob. 52PPSE Ch. 5.8 - Prob. 53PPSE Ch. 5.8 - Prob. 54PPSE Ch. 5.8 - Prob. 55PPSE Ch. 5.8 - Prob. 56PPSE Ch. 5.8 - Prob. 57PPSE Ch. 5.8 - Prob. 58PPSE Ch. 5.9 - Prob. 1LC Ch. 5.9 - Prob. 2LC Ch. 5.9 - Prob. 3LC Ch. 5.9 - Prob. 4LC Ch. 5.9 - Prob. 5LC Ch. 5.9 - Prob. 6LC Ch. 5.9 - Prob. 7PPSE Ch. 5.9 - Prob. 8PPSE Ch. 5.9 - Prob. 9PPSE Ch. 5.9 - Prob. 10PPSE Ch. 5.9 - Prob. 11PPSE Ch. 5.9 - Prob. 12PPSE Ch. 5.9 - Prob. 13PPSE Ch. 5.9 - Prob. 14PPSE Ch. 5.9 - Prob. 15PPSE Ch. 5.9 - Prob. 16PPSE Ch. 5.9 - Prob. 17PPSE Ch. 5.9 - Prob. 18PPSE Ch. 5.9 - Prob. 19PPSE Ch. 5.9 - Prob. 20PPSE Ch. 5.9 - Prob. 21PPSE Ch. 5.9 - Prob. 22PPSE Ch. 5.9 - Prob. 23PPSE Ch. 5.9 - Prob. 24PPSE Ch. 5.9 - Prob. 25PPSE Ch. 5.9 - Prob. 26PPSE Ch. 5.9 - Prob. 27PPSE Ch. 5.9 - Prob. 28PPSE Ch. 5.9 - Prob. 29PPSE Ch. 5.9 - Prob. 30PPSE Ch. 5.9 - Prob. 31PPSE Ch. 5.9 - Prob. 32PPSE Ch. 5.9 - Prob. 33PPSE Ch. 5.9 - Prob. 34PPSE Ch. 5.9 - Prob. 35PPSE Ch. 5.9 - Prob. 36PPSE Ch. 5.9 - Prob. 37PPSE Ch. 5.9 - Prob. 38PPSE Ch. 5.9 - Prob. 39PPSE Ch. 5.9 - Prob. 40PPSE Ch. 5.9 - Prob. 41PPSE Ch. 5.9 - Prob. 42PPSE Ch. 5.9 - Prob. 43PPSE Ch. 5.9 - Prob. 44PPSE Ch. 5.9 - Prob. 45PPSE Ch. 5.9 - Prob. 46PPSE Ch. 5.9 - Prob. 47PPSE Ch. 5.9 - Prob. 48PPSE Ch. 5.9 - Prob. 49PPSE Ch. 5.9 - Prob. 50PPSE Ch. 5.9 - Prob. 51PPSE Ch. 5.9 - Prob. 52PPSE Ch. 5.9 - Prob. 53PPSE Ch. 5.9 - Prob. 54PPSE Ch. 5.9 - Prob. 55PPSE Ch. 5.9 - Prob. 56PPSE Ch. 5 - Prob. 1GR Ch. 5 - Prob. 2GR Ch. 5 - Prob. 3GR Ch. 5 - Prob. 4GR Ch. 5 - Prob. 5GR Ch. 5 - Prob. 6GR Ch. 5 - Prob. 7GR Ch. 5 - Prob. 8GR Ch. 5 - Prob. 9GR Ch. 5 - Prob. 10GR Ch. 5 - Prob. 11GR Ch. 5 - Prob. 12GR Ch. 5 - Prob. 13GR Ch. 5 - Prob. 14GR Ch. 5 - Prob. 15GR Ch. 5 - Prob. 16GR Ch. 5 - Prob. 17GR Ch. 5 - Prob. 18GR Ch. 5 - Prob. 1MCQ Ch. 5 - Prob. 2MCQ Ch. 5 - Prob. 3MCQ Ch. 5 - Prob. 4MCQ Ch. 5 - Prob. 5MCQ Ch. 5 - Prob. 6MCQ Ch. 5 - Prob. 7MCQ Ch. 5 - Prob. 8MCQ Ch. 5 - Prob. 9MCQ Ch. 5 - Prob. 10MCQ Ch. 5 - Prob. 11MCQ Ch. 5 - Prob. 12MCQ Ch. 5 - Prob. 13MCQ Ch. 5 - Prob. 14MCQ Ch. 5 - Prob. 15MCQ Ch. 5 - Prob. 16MCQ Ch. 5 - Prob. 17MCQ Ch. 5 - Prob. 18MCQ Ch. 5 - Prob. 19MCQ Ch. 5 - Prob. 1CV Ch. 5 - Prob. 2CV Ch. 5 - Prob. 3CV Ch. 5 - Prob. 4CV Ch. 5 - Prob. 5E Ch. 5 - Prob. 6E Ch. 5 - Prob. 7E Ch. 5 - Prob. 8E Ch. 5 - Prob. 9E Ch. 5 - Prob. 10E Ch. 5 - Prob. 11E Ch. 5 - Prob. 12E Ch. 5 - Prob. 13E Ch. 5 - Prob. 14E Ch. 5 - Prob. 15E Ch. 5 - Prob. 16E Ch. 5 - Prob. 17E Ch. 5 - Prob. 18E Ch. 5 - Prob. 19E Ch. 5 - Prob. 20E Ch. 5 - Prob. 21E Ch. 5 - Prob. 22E Ch. 5 - Prob. 23E Ch. 5 - Prob. 24E Ch. 5 - Prob. 25E Ch. 5 - Prob. 26E Ch. 5 - Prob. 27E Ch. 5 - Prob. 28E Ch. 5 - Prob. 29E Ch. 5 - Prob. 30E Ch. 5 - Prob. 31E Ch. 5 - Prob. 32E Ch. 5 - Prob. 33E Ch. 5 - Prob. 34E Ch. 5 - Prob. 35E Ch. 5 - Prob. 36E Ch. 5 - Prob. 37E Ch. 5 - Prob. 38E Ch. 5 - Prob. 39E Ch. 5 - Prob. 40E Ch. 5 - Prob. 41E Ch. 5 - Prob. 42E Ch. 5 - Prob. 43E Ch. 5 - Prob. 44E Ch. 5 - Prob. 45E Ch. 5 - Prob. 46E Ch. 5 - Prob. 47E Ch. 5 - Prob. 48E Ch. 5 - Prob. 49E Ch. 5 - Prob. 50E Ch. 5 - Prob. 51E Ch. 5 - Prob. 52E Ch. 5 - Prob. 53E Ch. 5 - Prob. 54E Ch. 5 - Prob. 55E Ch. 5 - Prob. 56E Ch. 5 - Prob. 57E Ch. 5 - Prob. 58E Ch. 5 - Prob. 59E Ch. 5 - Prob. 60E Ch. 5 - Prob. 61E Ch. 5 - Prob. 62E Ch. 5 - Prob. 63E Ch. 5 - Prob. 64E Ch. 5 - Prob. 65E Ch. 5 - Prob. 66E Ch. 5 - Prob. 67E Ch. 5 - Prob. 68E Ch. 5 - Prob. 69E Ch. 5 - Prob. 70E Ch. 5 - Prob. 71E Ch. 5 - Prob. 72E Ch. 5 - Prob. 73E Ch. 5 - Prob. 74E Ch. 5 - Prob. 75E Ch. 5 - Prob. 76E Ch. 5 - Prob. 77E Ch. 5 - Prob. 78E Ch. 5 - Prob. 79E Ch. 5 - Prob. 80E Ch. 5 - Prob. 81E Ch. 5 - Prob. 82E Ch. 5 - Prob. 83E Ch. 5 - Prob. 84E Ch. 5 - Prob. 85E Ch. 5 - Prob. 86E Ch. 5 - Prob. 87E Ch. 5 - Prob. 88E Ch. 5 - Prob. 1CT Ch. 5 - Prob. 2CT Ch. 5 - Prob. 3CT Ch. 5 - Prob. 4CT Ch. 5 - Prob. 5CT Ch. 5 - Prob. 6CT Ch. 5 - Prob. 7CT Ch. 5 - Prob. 8CT Ch. 5 - Prob. 9CT Ch. 5 - Prob. 10CT Ch. 5 - Prob. 11CT Ch. 5 - Prob. 12CT Ch. 5 - Prob. 13CT Ch. 5 - Prob. 14CT Ch. 5 - Prob. 15CT Ch. 5 - Prob. 16CT Ch. 5 - Prob. 17CT Ch. 5 - Prob. 18CT Ch. 5 - Prob. 19CT Ch. 5 - Prob. 20CT Ch. 5 - Prob. 21CT Ch. 5 - Prob. 22CT Ch. 5 - Prob. 23CT Ch. 5 - Prob. 1CCSR Ch. 5 - Prob. 2CCSR Ch. 5 - Prob. 3CCSR Ch. 5 - Prob. 4CCSR Ch. 5 - Prob. 5CCSR Ch. 5 - Prob. 6CCSR Ch. 5 - Prob. 7CCSR Ch. 5 - Prob. 8CCSR Ch. 5 - Prob. 9CCSR Ch. 5 - Prob. 10CCSR Ch. 5 - Prob. 11CCSR Ch. 5 - Prob. 12CCSR Ch. 5 - Prob. 13CCSR Ch. 5 - Prob. 14CCSR Ch. 5 - Prob. 15CCSR Ch. 5 - Prob. 16CCSR Ch. 5 - Prob. 17CCSR Ch. 5 - Prob. 18CCSR Ch. 5 - Prob. 19CCSR Ch. 5 - Prob. 20CCSR Ch. 5 - Prob. 21CCSR Ch. 5 - Prob. 22CCSR Ch. 5 - Prob. 23CCSR

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