Chapter 5, Problem 1SE

A molecular biologist is studying the effectiveness of a particular enzyme to digest a certain sequence of DNA nucleotides. He divides six DNA samples into two parts, treats one part with the enzyme, and leaves the other part untreated. He then uses a polymerase chain reaction assay to count the number of DNA fragments that contain the given sequence. The results are as follows:

Find a 95% confidence interval for the difference between the mean numbers of fragments.

To determine

Find the 95% confidence interval for the difference between the mean number of fragments.

Answer to Problem 1SE

The 95% confidence interval for the difference between the mean number of fragments is $\underset{\_}{\left(1.943,19.724\right)}$.

Explanation of Solution

Given info:

In the study, six DNA samples into two parts, treats one part with the enzyme and leaves the other part untreated. Also, count the number of DNA fragments that contain the given sequence.

Calculation:

Confidence interval:

Software Procedure:

Step-by-step procedure to obtain the confidence interval using the MINITAB software:

• Choose Stat > Basic Statistics > Paired t.
• In First Sample, enter the column of Enzyme absent.
• In Second Sample, enter the column of Enzyme present.
• Check Options; enter Confidence level as 95%.
• Choose not equal in alternative.
• Click OK.

Output using the MINITAB software is given below:

From the output, the 95% confidence interval for the difference between the mean number of fragments is $\underset{\_}{\left(1.943,19.724\right)}$.