[10] In some applications the distribution of a discrete RV, X resembles the Poisson distribution except that 0 is not a possible value of X. Consider such a RV with PMF e- Px(x) = c x = 1, 2, .... x! where > 0 is a parameter, and c is a constant. (a) Find the expression of c in terms of X. 1 (b) Find E(X). (Hint: You can use the fact that, if Y~Poisson (A), the E(Y) = A.)
[10] In some applications the distribution of a discrete RV, X resembles the Poisson distribution except that 0 is not a possible value of X. Consider such a RV with PMF e- Px(x) = c x = 1, 2, .... x! where > 0 is a parameter, and c is a constant. (a) Find the expression of c in terms of X. 1 (b) Find E(X). (Hint: You can use the fact that, if Y~Poisson (A), the E(Y) = A.)
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.1: Measures Of Center
Problem 9PPS
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In some applications the distribution of a discrete RV, X resembles the Poisson distribution except that 0 is not a possible value of X. Consider such a RV with PMF
where 1 > 0 is a parameter, and c is a constant.
(a) Find the expression of c in terms of 1.
(b) Find E(X).
(Hint: You can use the fact that, if Y ~ Poisson(1), the E(Y) = 1.)
![[10] In some applications the distribution of a discrete RV, X resembles the Poisson
distribution except that 0 is not a possible value of X. Consider such a RV with PMF
e-
Px(x) = c
x = 1, 2, ....
x!
where > 0 is a parameter, and c is a constant.
(a) Find the expression of c in terms of X.
1
(b) Find E(X).
(Hint: You can use the fact that, if Y~Poisson (A), the E(Y) = A.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff608d3a0-7ad6-4d87-98f1-9a851954d279%2Fbf6e0dbe-7e32-45c2-8cf2-971005d78594%2Fxhvfsr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:[10] In some applications the distribution of a discrete RV, X resembles the Poisson
distribution except that 0 is not a possible value of X. Consider such a RV with PMF
e-
Px(x) = c
x = 1, 2, ....
x!
where > 0 is a parameter, and c is a constant.
(a) Find the expression of c in terms of X.
1
(b) Find E(X).
(Hint: You can use the fact that, if Y~Poisson (A), the E(Y) = A.)
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