An article suggested that under some circumstances the distribution of waiting time X could be modeled with the following pdf. 0-1 Fx; 8, t) = otherwise (a) Graph f(x; 0, 80) for the three cases 6 = 3, 1, and 0.5 and comment on their shapes. f(x) f(x) f(x) 0.05 0=0.5 0.05 = 05 0.05 0 = 0.5 0.04 0.04 0.04 0.03 0.03 0.03 0.02| 0.02 0.02 0=1 0.01 0.01 0.01 20 40 60 80 20 40 60 80 20 40 (b) Obtain the cumulative distribution function of X. F(X) = 0

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b) c) d)
An article suggested that under some circumstances the distribution of waiting time X could be modeled with the following pdf.
Fx; 8, t) =
otherwise
(a) Graph f(x; 0, 80) for the three cases 6 = 3, 1, and 0.5 and comment on their shapes.
f(X)
f(x)
f(x)
0.05
0=0.5
0.05 = 05
0.05 0 = 0.5
0.04
0.04
0.04
0.03
0.03
0.03
0.02
0.02
0.02
0.01
0.01
0.01
20
40
60
80
20
40
60
80
20
40
(b) Obtain the cumulative distribution function of X.
x <0
F(X) =
0 <x< T
1
(c) Obtain an expression for the median of the waiting time distribution.
(d) For the case e = 3, 1 = 80, calculate P(30 <X S 70) without at this point doing any additional integration. (Round your answer to four decimal places.)
Transcribed Image Text:An article suggested that under some circumstances the distribution of waiting time X could be modeled with the following pdf. Fx; 8, t) = otherwise (a) Graph f(x; 0, 80) for the three cases 6 = 3, 1, and 0.5 and comment on their shapes. f(X) f(x) f(x) 0.05 0=0.5 0.05 = 05 0.05 0 = 0.5 0.04 0.04 0.04 0.03 0.03 0.03 0.02 0.02 0.02 0.01 0.01 0.01 20 40 60 80 20 40 60 80 20 40 (b) Obtain the cumulative distribution function of X. x <0 F(X) = 0 <x< T 1 (c) Obtain an expression for the median of the waiting time distribution. (d) For the case e = 3, 1 = 80, calculate P(30 <X S 70) without at this point doing any additional integration. (Round your answer to four decimal places.)
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