UNDERSTANDING THE UNIVERSE(LL)-W/CODE
3rd Edition
ISBN: 9780393869903
Author: PALEN
Publisher: NORTON
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Chapter 5, Problem 17QAP
To determine
The reason for clumps to grow into planetesimals.
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7. An electron has been placed at the origin. The grid spacing is 1 Angstrom per small square this time. You put a nucleus with 9 protons on the x-axis at x = 3.0 Angstroms. There will be a place on the x-axis where the total electric field is zero. At what value of x does this occur?
0.18 Angstroms
-1.50 Angstroms
-0.60 Angstroms
0.36 Angstroms
4) There is a 2 C point charge at the origin and a 1 C point
charge on the x axis at x= 1 meter. Where on the x axis (at
finite x) would the electric field be zero? What if the charge at
X = 1 meter was -1C?
5) How strong would an electric field need to be to accelerate
an electron at 1,000,000 meters per second squared?
6) You go to the science museum and put your hand on the
metal ball and your hair sticks up straight, and you know,
science. Briefly explain why this happens to Mr. Scott's hair.
(The metal ball is the charged top of a Van de Graaff
generator.)
9%) Problem 1: An archaeon has 7.3 × 10¹6 protons and a net charge of 1.5 pC.
50% Part (a) How many fewer electrons are there than protons?
Np - Ne
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Chapter 5 Solutions
UNDERSTANDING THE UNIVERSE(LL)-W/CODE
Ch. 5.1 - Prob. 5.1CYUCh. 5.2 - Prob. 5.2CYUCh. 5.3 - Prob. 5.3CYUCh. 5.4 - Prob. 5.4CYUCh. 5.5 - Prob. 5.5CYUCh. 5.6 - Prob. 5.6CYUCh. 5 - Prob. 1QAPCh. 5 - Prob. 2QAPCh. 5 - Prob. 3QAPCh. 5 - Prob. 4QAP
Ch. 5 - Prob. 5QAPCh. 5 - Prob. 6QAPCh. 5 - Prob. 7QAPCh. 5 - Prob. 8QAPCh. 5 - Prob. 9QAPCh. 5 - Prob. 10QAPCh. 5 - Prob. 11QAPCh. 5 - Prob. 12QAPCh. 5 - Prob. 13QAPCh. 5 - Prob. 14QAPCh. 5 - Prob. 15QAPCh. 5 - Prob. 16QAPCh. 5 - Prob. 17QAPCh. 5 - Prob. 18QAPCh. 5 - Prob. 19QAPCh. 5 - Prob. 20QAPCh. 5 - Prob. 21QAPCh. 5 - Prob. 22QAPCh. 5 - Prob. 23QAPCh. 5 - Prob. 24QAPCh. 5 - Prob. 25QAPCh. 5 - Prob. 27QAPCh. 5 - Prob. 28QAPCh. 5 - Prob. 29QAPCh. 5 - Prob. 30QAPCh. 5 - Prob. 31QAPCh. 5 - Prob. 32QAPCh. 5 - Prob. 34QAPCh. 5 - Prob. 35QAPCh. 5 - Prob. 36QAPCh. 5 - Prob. 37QAPCh. 5 - Prob. 38QAPCh. 5 - Prob. 39QAPCh. 5 - Prob. 40QAPCh. 5 - Prob. 41QAPCh. 5 - Prob. 42QAPCh. 5 - Prob. 43QAPCh. 5 - Prob. 44QAPCh. 5 - Prob. 45QAP
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- 1.How many coulombs of positive charge are there in 1.20 kg of plutonium, given that its atomic mass is 244 and each plutonium atom has 94 protons? ___c 2.Red blood cells can often be charged. Consider two red blood cells with the following charges: −22.2 pC and +53.8 pC. The red blood cells are 4.29 cm apart. (1 pC = 1 ✕ 10−12 C.) (a) What is the magnitude of the force on each red blood cell?____________ N(b) The red blood cells come into contact with each other and then are separated by 4.29 cm. What magnitude of force does each of the red blood cells now experience?____________ Narrow_forward8:28 93 lecture 1 electricity.. the electric field in space. [Field lines for positive (radially outward) and negative charges (radially inward).] [Field lines for an electric dipole (a pair of charges of equal magnitude but opposite sign)] * The properties of electric field lines: > The direction of the electric field vector E at a point is tangent to the field lines. - The number of lines per unit area through a surface perpendicular to the line is devised to be proportional to the magnitude of the electric field in a given region. - The field lines must begin on positive charges (or at infinity) and then teminate on negative charges (or at infinity). - The number of lines that originate from a positive charge or terminating on a negative charge must be proportional to the magnitude of the charge. - No two field lines can cross each other; otherwise the field would be pointing in two different directions at the same point. H.W 1. Two opposite charges are placed on a line as shown in…arrow_forward2.Two-point charges are arranged on the x-y coordinate system as follows: q. = 4 x 108 C at (0,3 m) and q2 = -9 x 107 C at (5,0 m). Find the electric origin at (0,0). Using the Pythagorean theorem calculate for the magnitude E of the resultant electric field.arrow_forward
- 2. If two protons lived in a universe where they were both far more massive than protons in our universe, but still had the same charge, calculate the mass that each proton would have if the gravitational force of attraction between them would exactly balance the electrostatic repulsion they experience. (Assume G and ɛ, are the same as in our universe and that the charge on each proton is 1.6 x 10-19 C.)arrow_forward6. Three identical particles of mass m and charge q each are fixed at the vertices of an equilateral triangle with side a. What maximal velocity will each of the balls acquire if they are allowed to move freely? Calculate for the electron if a = 10^-8 m.arrow_forward1. Each of two small non-conducting spheres is charged positively, the combined charge being 40 pC. If each sphere is repelled from the other by a force having a magnitude of 2.0 N when the two spheres are 50 cm apart, determine the charge on the sphere having the smaller charge.arrow_forward
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