In the presence of nitric acid, UO 2+ undergoes a redox process. It is converted to UO 2 2+ and nitric oxide (NO) gas is produced according to the following unbalanced equation: H + ( a q ) + NO 3 − ( a q ) + UO 2+ ( a q ) → NO ( g ) + UO 2 2 + ( a q ) + H 2 O ( l ) If 2.55 × 10 2 mL NO( g ) is isolated at 29°C and 1.5 atm, what amount (moles) of UO 2+ was used in the reaction? (Hint: Balance the reaction by the oxidation states method.)
In the presence of nitric acid, UO 2+ undergoes a redox process. It is converted to UO 2 2+ and nitric oxide (NO) gas is produced according to the following unbalanced equation: H + ( a q ) + NO 3 − ( a q ) + UO 2+ ( a q ) → NO ( g ) + UO 2 2 + ( a q ) + H 2 O ( l ) If 2.55 × 10 2 mL NO( g ) is isolated at 29°C and 1.5 atm, what amount (moles) of UO 2+ was used in the reaction? (Hint: Balance the reaction by the oxidation states method.)
Solution Summary: The author explains the balance equation of a reaction, which is written according to law of conservation of mass.
In the presence of nitric acid, UO2+ undergoes a redox process. It is converted to UO22+ and nitric oxide (NO) gas is produced according to the following unbalanced equation:
H
+
(
a
q
)
+
NO
3
−
(
a
q
)
+
UO
2+
(
a
q
)
→
NO
(
g
)
+
UO
2
2 +
(
a
q
)
+
H
2
O
(
l
)
If 2.55 × 102 mL NO(g) is isolated at 29°C and 1.5 atm, what amount (moles) of UO2+ was used in the reaction? (Hint: Balance the reaction by the oxidation states method.)
The azide ion is N3^-. In addition to the ionic charge, it’s three mostimportant contributing structures also have formal charges. The totalnumber of π bonds in these three contributing structures isA. 6; B. 12; C. 3; D. 9; E. None of the other answers is correct.
The sum of the numerals in the name of the compoundis A. None of the other answers is correct.; B. 11;C. 6; D. 8; E. 5.
A compound has a six carbon ring with three double bonds. Attachedto the ring is a three carbon chain with a triple bond and a two carbonchain with two bromines attached. The number of hydrogens in a
molecule of this compound is A. 10; B. 12; C. 14; D. 13; E. None
of the other answers is correct.
Chapter 5 Solutions
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