In the presence of nitric acid, UO 2+ undergoes a redox process. It is converted to UO 2 2+ and nitric oxide (NO) gas is produced according to the following unbalanced equation: H + ( a q ) + NO 3 − ( a q ) + UO 2+ ( a q ) → NO ( g ) + UO 2 2 + ( a q ) + H 2 O ( l ) If 2.55 × 10 2 mL NO( g ) is isolated at 29°C and 1.5 atm, what amount (moles) of UO 2+ was used in the reaction? (Hint: Balance the reaction by the oxidation states method.)
In the presence of nitric acid, UO 2+ undergoes a redox process. It is converted to UO 2 2+ and nitric oxide (NO) gas is produced according to the following unbalanced equation: H + ( a q ) + NO 3 − ( a q ) + UO 2+ ( a q ) → NO ( g ) + UO 2 2 + ( a q ) + H 2 O ( l ) If 2.55 × 10 2 mL NO( g ) is isolated at 29°C and 1.5 atm, what amount (moles) of UO 2+ was used in the reaction? (Hint: Balance the reaction by the oxidation states method.)
Solution Summary: The author explains the balance equation of a reaction, which is written according to law of conservation of mass.
In the presence of nitric acid, UO2+ undergoes a redox process. It is converted to UO22+ and nitric oxide (NO) gas is produced according to the following unbalanced equation:
H
+
(
a
q
)
+
NO
3
−
(
a
q
)
+
UO
2+
(
a
q
)
→
NO
(
g
)
+
UO
2
2 +
(
a
q
)
+
H
2
O
(
l
)
If 2.55 × 102 mL NO(g) is isolated at 29°C and 1.5 atm, what amount (moles) of UO2+ was used in the reaction? (Hint: Balance the reaction by the oxidation states method.)
3. Devise a retrosynthesis for the problem given below and then provide the corresponding
synthesis with all necessary reagents/reactants:
RETROSYNTHESIS:
SYNTHESIS:
Br
Several square planar complexes are known for Gold (III) ions but not for Silver (III) why?
Aiter running various experiments, you determine that the mechanism for the following reaction is bimolecular.
CI
Using this information, draw the correct mechanism in the space below.
X
Explanation
Check
C
Cl
OH + CI
Add/Remove step
Click and drag to start
drawing a structure.
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