Chapter 5, Problem 110AE

The Sun supplies about 1.0 kilowatt of energy for each squaremeter of surface area (1.0 kW/m²,where a watt = 1 J/s). Plants produce the equivalent of about 0.20 g of sucrose (C₁₂H₂₂O₁₁) per hour per square meter. Assuming that the sucrose is produced as follows, calculate the percentage ofsunlight used to produce sucrose.

${\text{12CO}}_{\text{2}}\text{(g)}\text{+}{\text{11H}}_{\text{2}}\text{O(l)}\to {\text{C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{\text{11}}\text{+}{\text{12O}}_{\text{2}}\text{(g)}\Delta \text{H}\text{=}\text{5645}\text{kJ}$