Electronics Fundamentals: Circuits, Devices & Applications
8th Edition
ISBN: 9780135072950
Author: Thomas L. Floyd, David Buchla
Publisher: Prentice Hall
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Chapter 5, Problem 10ST
To determine
To find: The current in three other branches.
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Chapter 5 Solutions
Electronics Fundamentals: Circuits, Devices & Applications
Ch. 5 - Prob. 1TFQCh. 5 - The total resistance of parallel resistors is...Ch. 5 - The product-over-sum rule works for any number of...Ch. 5 - In a parallel circuit, the voltage is larger on a...Ch. 5 - Prob. 5TFQCh. 5 - Prob. 6TFQCh. 5 - Prob. 7TFQCh. 5 - In the current-divider formula, Ix=(RT/Rx)lT, the...Ch. 5 - Prob. 9TFQCh. 5 - The total power dissipated by parallel resistors...
Ch. 5 - In a parallel circuit, each resistor has the same...Ch. 5 - When a 1.2k resistor and a 100 resistor are...Ch. 5 - Prob. 3STCh. 5 - Eight resistors are in parallel. The two...Ch. 5 - When an additional resistor is connected across an...Ch. 5 - If one of the resistors in a parallel circuit is...Ch. 5 - The currents into a node are along two paths. One...Ch. 5 - Prob. 8STCh. 5 - Prob. 9STCh. 5 - Prob. 10STCh. 5 - In a certain three-branch parallel circuit,...Ch. 5 - Prob. 12STCh. 5 - Prob. 13STCh. 5 - Prob. 14STCh. 5 - Determine the cause for each set of symptoms....Ch. 5 - Prob. 2TSCCh. 5 - Prob. 3TSCCh. 5 - Prob. 4TSCCh. 5 - Determine the cause for each set of symptoms....Ch. 5 - Connect the resistors in Figure 5-57 in parallel...Ch. 5 - Determine whether or not all the resistors in...Ch. 5 - Determine the total resistance between pins 1 and...Ch. 5 - The following resistors are connected in parallel:...Ch. 5 - Find the total resistance between nodes A and B...Ch. 5 - Calculate RT for each circuit in Figure 5-60.Ch. 5 - What is the total resistance of eleven 22k...Ch. 5 - Five 15, ten 100, and two 10 resistors are all...Ch. 5 - Determine the voltage across and the current...Ch. 5 - The source voltage in Figure 5-61 is 100 V. How...Ch. 5 - Prob. 11PCh. 5 - The resistance of a 60 W bulb is approximatey 240....Ch. 5 - What is the current in each resistor for the...Ch. 5 - Four equal-value resistors are connected in...Ch. 5 - The following currents are measured in the same...Ch. 5 - There is a total of 500mA of current into five...Ch. 5 - How much current is through R2 and R3 in Figure...Ch. 5 - A trailer has four running lights that draw 0.5A...Ch. 5 - Assume the trailer in Problem 18 has two brake...Ch. 5 - A 10k resistor and a 15k resistor are in parallel...Ch. 5 - How much branch current should each meter in...Ch. 5 - Prob. 22PCh. 5 - Five parallel resistors each handle 40mW. What is...Ch. 5 - Prob. 24PCh. 5 - Six light bulbs are connected in parallel across...Ch. 5 - If one of the bulbs burns out in Problem 25, how...Ch. 5 - In Figure 5-67, the current and voltage...Ch. 5 - Prob. 28PCh. 5 - Find the open resistor in Figure 5-69.Ch. 5 - From the ohmmeter reading in Figure 5-70, can you...Ch. 5 - In the circuit of Figure 5-71, determine...Ch. 5 - The total resistance of a parallel circuit is 25....Ch. 5 - What is the current through each resistor in...Ch. 5 - A certain parallel circuit consists of only 12W...Ch. 5 - Find the values of the unspecified quantities...Ch. 5 - What is the total resistance between terminal A...Ch. 5 - What value of R2 in Figure 5-75 will cause...Ch. 5 - Determine the total current from the source and...Ch. 5 - The electrical circuit in a room is protected with...Ch. 5 - The total resistance of a parallel circuit is 25....Ch. 5 - Prob. 41PCh. 5 - If the total resistance in Figure 5-78 is 200,...Ch. 5 - Determine the unknown resistances in Figure 5-79.Ch. 5 - There is a total of 250 mA into a parallel circuit...Ch. 5 - Prob. 45PCh. 5 - Develop a test procedure to check the circuit in...Ch. 5 - A certain parallel circuit consists of five 12W...Ch. 5 - For the circuit board shown in Figure 5-82,...Ch. 5 - For the circuit board shown in Figure 5-82,...Ch. 5 - Open file P05-50; files are found at...Ch. 5 - Open file P05-51. Using current measurements,...Ch. 5 - Open file P05-52. Using current measurements,...
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- Imaginary Axis (seconds) 1 6. Root locus for a closed-loop system with L(s) = is shown below. s(s+4)(s+6) 15 10- 0.89 0.95 0.988 0.988 -10 0.95 -15 -25 0.89 20 Root Locus 0.81 0.7 0.56 0.38 0.2 5 10 15 System: sys Gain: 239 Pole: -0.00417 +4.89 Damping: 0.000854 Overshoot (%): 99.7 Frequency (rad/s): 4.89 System: sys Gain: 16.9 Pole: -1.57 Damping: 1 Overshoot (%): 0 Frequency (rad/s): 1.57 0.81 0.7 0.56 0.38 0.2 -20 -15 -10 -5 5 10 Real Axis (seconds) From the values shown in the figure, compute the following. a) Range of K for which the closed-loop system is stable. b) Range of K for which the closed-loop step response will not have any overshoot. Note that when all poles are real, the step response has no overshoot. c) Smallest possible peak time of the system. Note that peak time is the smallest when wa is the largest for the dominant pole. d) Smallest possible settling time of the system. Note that peak time is the smallest when σ is the largest for the dominant pole.arrow_forwardFor a band-rejection filter, the response drops below this half power point at two locations as visualised in Figure 7, we need to find these frequencies. Let's call the lower frequency-3dB point as fr and the higher frequency -3dB point fH. We can then find out the bandwidth as f=fHfL, as illustrated in Figure 7. 0dB Af -3 dB Figure 7. Band reject filter response diagram Considering your AC simulation frequency response and referring to Figure 7, measure the following from your AC simulation. 1% accuracy: (a) Upper-3db Frequency (fH) = Hz (b) Lower-3db Frequency (fL) = Hz (c) Bandwidth (Aƒ) = Hz (d) Quality Factor (Q) =arrow_forwardP 4.4-21 Determine the values of the node voltages V1, V2, and v3 for the circuit shown in Figure P 4.4-21. 29 ww 12 V +51 Aia ww 22. +21 ΖΩ www ΖΩ w +371 ①1 1 Aarrow_forward
- 1. What is the theoretical attenuation of the output voltage at the resonant frequency? Answer to within 1%, or enter 0, or infinity (as “inf”) Attenuation =arrow_forwardWhat is the settling time for your output signal (BRF_OUT)? For this question, We define the settling time as the period of time it has taken for the output to settle into a steady state - ie when your oscillation first decays (aka reduces) to less than approximately 1/20 (5%) of the initial value. (a) Settling time = 22 μs Your last answer was interpreted as follows: Incorrect answer. Check 22 222 What is the peak to peak output voltage (BRF_OUT pp) at the steady state condition? You may need to use the zoom function to perform this calculation. Select a time point that is two times the settling time you answered in the question above. Answer to within 10% accuracy. (a) BRF_OUT pp= mVpp As you may have noticed, the output voltage amplitude is a tiny fraction of the input voltage, i.e. it has been significantly attenuated. Calculate the attenuation (decibels = dB) in the output signal as compared to the input based on the formula given below. Answer to within 1% accuracy.…arrow_forwardmy previous answers for a,b,d were wrong a = 1050 b = 950 d=9.99 c was the only correct value i got previously c = 100hz is correctarrow_forward
- V₁(t) ww ZRI ZLI ZL2 ZTH Zci VTH Zc21 Figure 8. Circuit diagram showing calculation approach for VTH and Z TH we want to create a blackbox for the red region, we want to use the same input signal conditions as previously the design of your interference ector circuit: Sine wave with a 1 Vpp, with a frequency of 100 kHz (interference) Square wave with 2.4Vpp, with a frequency of 10 kHz (signal) member an AC Thevenin equivalent is only valid at one frequency. We have chosen to calculate the Thevenin equivalent circuit (and therefore the ackbox) at the interference frequency (i.e. 100 kHz), and the signal frequency (i.e. 10 kHz) as these are the key frequencies to analyse. Your boss is assured you that the waveform converter module has been pre-optimised to the DAB Receiver if you use the recommended circuit topology.arrow_forwardVs(t) + v(t) + vi(t) ZR ZL Figure 1: Second order RLC circuit Zc + ve(t) You are requested to design the circuit shown in Figure 1. The circuit is assumed to be operating at its resonant frequency when it is fed by a sinusoidal voltage source Vs (t) = 2sin(le6t). To help design your circuit you have been given the value of inductive reactance ZL = j1000. Assume that the amplitude of the current at resonance is Is (t) = 2 mA. Based on this information, answer the following to help design your circuit. Use cartesian notation for your answers, where required.arrow_forwardWhat is the attenuation at the resonant frequency? You should use the LTSpice cursors for your measurement. Answer to within 1% accuracy, or enter 0, or infinity (as "inf") (a) Attenuation (dB) = dB Check You may have noticed that it was significantly easier to use frequency-domain "AC" simulation to measure the attenuation, compared to the steps we performed in the last few questions. (i.e. via a time-domain "transient" simulation). AC analysis allows us to observe and quantify large scale positive or negative changes in a signal of interest across a wide range of different frequencies. From the response you will notice that only frequencies that are relatively close to 100 kHz have been attenuated. This is the result of the Band-reject filter you have designed, and shows the 'rejection' (aka attenuation) of any frequencies that lie in a given band. The obvious follow-up question is how do we define this band? We use a quantity known as the bandwidth. A commonly used measurement for…arrow_forward
- V₁(t) ww ZRI ZLI ZL2 ZTH Zci VTH Zc21 Figure 8. Circuit diagram showing calculation approach for VTH and Z TH we want to create a blackbox for the red region, we want to use the same input signal conditions as previously the design of your interference ector circuit: Sine wave with a 1 Vpp, with a frequency of 100 kHz (interference) Square wave with 2.4Vpp, with a frequency of 10 kHz (signal) member an AC Thevenin equivalent is only valid at one frequency. We have chosen to calculate the Thevenin equivalent circuit (and therefore the ackbox) at the interference frequency (i.e. 100 kHz), and the signal frequency (i.e. 10 kHz) as these are the key frequencies to analyse. Your boss is assured you that the waveform converter module has been pre-optimised to the DAB Receiver if you use the recommended circuit topology.arrow_forwardVs(t) + v(t) + vi(t) ZR ZL Figure 1: Second order RLC circuit Zc + ve(t) You are requested to design the circuit shown in Figure 1. The circuit is assumed to be operating at its resonant frequency when it is fed by a sinusoidal voltage source Vs (t) = 2sin(le6t). To help design your circuit you have been given the value of inductive reactance ZL = j1000. Assume that the amplitude of the current at resonance is Is (t) = 2 mA. Based on this information, answer the following to help design your circuit. Use cartesian notation for your answers, where required.arrow_forwardFor a band-rejection filter, the response drops below this half power point at two locations as visualised in Figure 7, we need to find these frequencies. Let's call the lower frequency-3dB point as fr and the higher frequency -3dB point fH. We can then find out the bandwidth as f=fHfL, as illustrated in Figure 7. 0dB Af -3 dB Figure 7. Band reject filter response diagram Considering your AC simulation frequency response and referring to Figure 7, measure the following from your AC simulation. 1% accuracy: (a) Upper-3db Frequency (fH) = Hz (b) Lower-3db Frequency (fL) = Hz (c) Bandwidth (Aƒ) = Hz (d) Quality Factor (Q) =arrow_forward
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