
(a)
Interpretation: The elements with the given electronic configuration should be identified as a metal, non-metal or metalloid.
Concept introduction: The rules for the allowed quantum numbers combinations are as follows:
- All the three quantum numbers ( n, l and m ) describes the orbital of an atom and they are integers.
- The principal quantum number, n value cannot be zero. Thus, the values allowed for the principal quantum number are 1, 2, 3, 4, and so on.
- The value of angular quantum number, l can be between 0 to n-1. Thus, if value of n is equal to 3 the value of l can be 0, 1 or 2.
- The value of magnetic quantum number, m can be between − l to +l . Thus, if value of l is equal to 2, m can be either -2, -1, 0, +1, or +2
For same number of principal quantum number, an orbital form a shell. The first character denotes the shell and the second identifies the sub-shell.
Here, for s orbital value of
The relative energy of orbitals is represented as follows:
A s orbital can have maximum of 2 electrons, p orbital can have maximum of 6 electrons. Similarly, maximum electrons that a d and f orbital can have are 10 and 14 respectively.
(b)
Interpretation: The element with the largest atomic size should be identified.
Concept Introduction: According to the periodic trends, the atomic size of the element increases on moving top to bottom in a group due to addition of one shell and decreases on moving left to right in a group due to increase in atomic number.
(c)
Interpretation: The element with the highest ionization energy should be identified.
Concept Introduction: Ionization energy is defined as the amount of energy required to remove an electron from its outermost shell. According to periodic trends, it decreases on moving top to bottom in a group due to increase in size and it increases on moving left to right in a period due to decrease in size.
(d)
Interpretation: The element with the smallest atomic size.
Concept Introduction: According to the periodic trends, the atomic size of the element increases on moving top to bottom in a group due to addition of one shell and decreases on moving left to right in a group due to increase in atomic number.

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Chapter 5 Solutions
EBK BASIC CHEMISTRY
- What alkene or alkyne yields the following products after oxidative cleavage with ozone? Click the "draw structure" button to launch the drawing utility. and two equivalents of CH2=O draw structure ...arrow_forwardH-Br Energy 1) Draw the step-by-step mechanism by which 3-methylbut-1-ene is converted into 2-bromo-2-methylbutane. 2) Sketch a reaction coordinate diagram that shows how the internal energy (Y- axis) of the reacting species change from reactants to intermediate(s) to product. Brarrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 H-CI CH2Cl2 CIarrow_forward
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- Draw the products of the stronger acid protonating the other reactant. H3C-C=C-4 NH2 KEq CH H3C `CH3 Product acid Product basearrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 Br H-Br CH2Cl2 + enant.arrow_forwardDraw the products of the stronger acid protonating the other reactant. KEq H₂C-O-H H3C OH Product acid Product basearrow_forward
- Draw the products of the stronger acid protonating the other reactant. OH KEq CH H3C H3C `CH3 Product acid Product basearrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). Ph H-I CH2Cl2arrow_forward3 attempts left Check my work Draw the products formed in the following oxidative cleavage. [1] 03 [2] H₂O draw structure ... lower mass product draw structure ... higher mass productarrow_forward
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning

