Chapter 4.8, Problem 3CYP

To determine

To Prove:

  $△ABX\cong △CDX$

Explanation of Solution

Given information:

  

Proof:

  $X$ is the mid point of $\overline{AC}$ , so $\overline{AX}=\overline{CX}$

  $\sphericalangle AXB\cong \sphericalangle CXD$ by V angular theorem.

  $X$ is the mid of $\overline{BD}$ , so $\overline{BX}\cong \overline{DX}$

So $△ABX\cong △CDX$ by S.A.S