Concept explainers
(a)
To Write: The conditional statement that shows the relationship between the areas of a pair of congruent
(a)
Answer to Problem 33PPS
If triangles are congruent, then they have the same area.
Explanation of Solution
Given information: The given statement is “the areas of congruent triangles are equal”.
As we know that congruent triangles have the same sides and equal three
Therefore, the two triangles will have the same area.
Hence, the conditional statement is ‘If triangles are congruent, then they have the same area’.
(b)
To explain: Whether the converse of conditional statement is true or false.
(b)
Answer to Problem 33PPS
The converse condition of conditional statement is false.
Explanation of Solution
Given information: If triangles are congruent, then they have the same area.
The converse of the conditional statement ‘If triangles are congruent, then they have the same area’ is ‘the triangles have the same area when they are congruent’.
We can see that these are false because two triangles can have the same area but can’t be congruent, depicted below.
Area of the first triangle,
Area of the second triangle,
Thus,
(c)
To explain: The possibility of two equilateral triangles can have the same area but are not congruent.
(c)
Answer to Problem 33PPS
It is impossible to have two non congruent equilateral triangles with the same areas.
Explanation of Solution
Given information: Two equilateral triangles are given.
Two non congruent triangles can’t have the same area because their side’s length and angles not equal.
(d)
To explain: The possibility of two rectangles can have the same area but are not congruent.
(d)
Answer to Problem 33PPS
Yes! It is possible to have two non congruent rectangles with the same area.
Explanation of Solution
Given information: Two non congruent rectangles are given.
Two non congruent triangles can have the same area.
But, we can see from the sketch that sides are not congruent.
Therefore,
(e)
To explain: The possibility of two squares can have the same area but are not congruent.
(e)
Answer to Problem 33PPS
No! It is not possible to have two non congruent squares with the same area.
Explanation of Solution
Given information: Two non congruent squares are given.
Two non congruent squares can’t have the same area.
As we know,
Where, s is side of square.
If the sides of the squares are equal, then its area will be equal. In this condition, its sides also become congruent.
Hence, it is not possible to draw two non congruent squares with the same area.
(f)
To find: The
(f)
Answer to Problem 33PPS
The given conditional statement is valid for regular polygons.
Explanation of Solution
Given information: The conditional statement is given, If a pair of ……. Are congruent, then they have the same area.
The given condition will be true only for equilateral triangle, squares and shapes that have all sides of the same length.
Therefore, we can say that it is valid for regular polygon.
Chapter 4 Solutions
Geometry, Student Edition
Additional Math Textbook Solutions
A First Course in Probability (10th Edition)
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
Algebra and Trigonometry (6th Edition)
University Calculus: Early Transcendentals (4th Edition)
Elementary Statistics: Picturing the World (7th Edition)
- Classwork for Geometry 1st X S Savvas Realize * MARYIA DASHUTSINA-Ba → CA savvasrealize.com/dashboard/classes/49ec9fc00d8f48ec9a4b05b30c9ee0ba A > SIS © = =Wauconda Middle S... 31 WMS 8th Grade Tea... SIS Grades and Attenda.... esc GEOMETRY 1ST < Study Guide T6 K 18 L 63° 9 N M Quadrilateral JKLM is a parallelogram. What is the m ZKJN? mZKJN = Review Progress acerarrow_forwardWhy is this proof incorrect? State what statement and/or reason is incorrect and why. Given: Overline OR is congruent to overline OQ, angle N is congruent to angle PProve: Angle 3 is congruent to angle 5 Why is this proof incorrect? Statements Reasons 1. Overline OR is congruent to overline OQ, angle N is congruent to angle P 1. Given 2. Overline ON is congruent to overline OP 2. Converse of the Isosceles Triangle Theorem 3. Triangle ONR is congruent to triangle OPQ 3. SAS 4. Angle 3 is congruent to angle 5 4. CPCTCarrow_forwardGiven: AABE ~ ACDE. Prove: AC bisects BD. Note: quadrilateral properties are not permitted in this proof. Step Statement Reason AABE ACDE Given 2 ZDEC ZAEB Vertical angles are congruent try Type of Statement A E B D Carrow_forward
- 2) Based on the given information and the diagram, a. Which congruence statements can be proven? Select all that apply.Given: Overline OR is congruent to overline OQ, angle N is congruent to angle PProve: angle 3 is congruent to angle 5A. Overline ON is congruent to overline OPB. Angle 1 is congruent to angle 2C. Overline ON is congruent to overline OR and overline OP is congruent to overine OQD. angle 1 is congruent to angle 3 and angle 2 is congruent to angle 5There are more than one correct answerarrow_forwardnt/Ray Skew Lines/ J K # H L 艹 G C D E F Diagrams m Three Points th a Protractor Answer Attempt 3 out of 3 el 1 is congruent to Submit Answer 103 Log Out REE Young the → C # $arrow_forward4:54 PM Thu Jan 16 cdn.assess.prod.mheducation.com Question 3 The angle bisectors of APQR are PZ, QZ, and RZ. They meet at a single point Z. (In other words, Z is the incenter of APQR.) Suppose YZ = 22, QZ = 23, mz WPY 38°, and mzXQZ = 54°. Find the following measures. Note that the figure is not drawn to scale. P W Z X R Y mzXQW WZ = = 0 mz XRZ = 0°arrow_forward
- Ja дх dx dx Q3: Define the linear functional J: H()-R by تاریخ (v) = ½a(v, v) - (v) == Let u be the unique weak solution to a(u,v) = L(v) in H₁(2) and suppose that a(...) is a symmetric bilinear form on H() prove that a Buy v) = 1- u is minimizer. 2- u is unique. 3- The minimizer J(u,) can be rewritten under J(u)=u' Au-ub, algebraic form Where A, b are repictively the stiffence matrix and the load vector Q4: A) Answer only 1-show that thelation to -Auf in N, u = 0 on a satisfies the stability Vulf and show that V(u-u,)||² = ||vu||2 - ||vu||2 lu-ulls Chu||2 2- Prove that Where =1 ||ul|= a(u, u) = Vu. Vu dx + fu. uds B) Consider the bilinear form a(u, v) = (Au, Av) + (Vu, Vv) + (Vu, v) + (u, v) Show that a(u, v) continues and V- elliptic on H(2) (3) (0.0), (3.0)arrow_forwardQ1: A) fill the following: 1- The number of triangular in a triangular region with 5 nodes is quadrilateral with n=5 and m=6 nodés is 2- The complex shape function in 1-D 3- dim(P4(K))=- (7M --- and in the and multiplex shape function in 2-D is 4- The trial space and test space for problem -Auf, u = go on and B) Define the energy norm and prove that the solution u, defined by Galerkin orthogonal satisfies the best approximation. Q2: A) Find the varitional form for the problem 1330 (b(x)) - x²=0, 0arrow_forwardcould you help?arrow_forward(ii)arrow_forwardA convex polygon is said to be regular if all of its sides have the same length and all angles between sides are the same. Let Pr denote the regular convex n-sided polygon. Thus, P3 is the equilateral triangle, P₁ is the square, P is the pentagon etc. Compute a formula for the size of any internal angle of Pn.arrow_forward+ Recall that a map, f: R2 R², is an isometry if |P-Q| = |ƒ(P) — ƒ (Q) for all pairs of points P and Q in R². Thus, f is a distance preserving map. Show that an isometry, f: R² → R² also preserves angles. In other words if two line segments meeting at a point determine an angle a, their image line segments meeting at the image of that point also determine the angle a.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
- Elementary Geometry For College Students, 7eGeometryISBN:9781337614085Author:Alexander, Daniel C.; Koeberlein, Geralyn M.Publisher:Cengage,Elementary Geometry for College StudentsGeometryISBN:9781285195698Author:Daniel C. Alexander, Geralyn M. KoeberleinPublisher:Cengage Learning