The distance d x (in feet) between an observer 30 ft from a straight highway and a police car traveling down the highway is given by d x = 30 sec x , where x is the angle (in degrees) between the observer and the police car. a. Use a calculator to evaluate d x for the given values of x . Round to the nearest foot. b. Try experimenting with values of x closer to 90 ∘ . What happens as x → 90 ∘ ?
The distance d x (in feet) between an observer 30 ft from a straight highway and a police car traveling down the highway is given by d x = 30 sec x , where x is the angle (in degrees) between the observer and the police car. a. Use a calculator to evaluate d x for the given values of x . Round to the nearest foot. b. Try experimenting with values of x closer to 90 ∘ . What happens as x → 90 ∘ ?
Solution Summary: The author calculates the distance d(x) between an observer 30 and a police car travelling down the highway using the trigonometric formula.
The distance
d
x
(in feet) between an observer
30
ft from a straight highway and a police car traveling down the highway is given by
d
x
=
30
sec
x
, where
x
is the angle (in degrees) between the observer and the police car.
a. Use a calculator to evaluate
d
x
for the given values of
x
. Round to the nearest foot.
b. Try experimenting with values of
x
closer to
90
∘
. What happens as
x
→
90
∘
?
Inverse laplace transform
Lect: Huda I
H.w
1- F(S)=
A- Find - F(s) of the following
S
(s+1)5
1
2- F(s)
s² (s-a)
5+5
3- F(s)=
s2+4s+3
1
4- F(s)=
(s+2)2(s-2)
3s2-7s+5
5- F(s)=
(s-1)(s2-5s+6)
Inverse laplace transform
Lect :Huda I
H.w
A- Find L-1 F(s) of the following
1- F(S)=
2- F(s)-
S
(+1)5
s² (s-a)
5+5
s2+4s+3
3- F(s)-
1
4- F(s)-
(s+2)2(s-2)
3s2-7s+5
5- F(s)-
(s-1)(s2-55+6)
B-Solve the D.E of the following:
1- y'+3y+2fy dt = f(t) for y(0)-1 if f(t) is the function
whose graph is shown below
2
1 2
2-y+4y-u(t)
for y(0)=y'(0)=0
3- y"+4y'+13y= e−2t sin3t
for y(0)-1 and y'(0)=-2
17
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