Chapter 4.6, Problem 24WE

To determine

To multiply: the expression $\left(3s+2\right)\left(2s^2-2s+1\right)$ using horizontal form.

Answer to Problem 24WE

The result of multiplication is $6s^3-2s^2-s+2$ .

Explanation of Solution

Given:

The expression is $\left(3s+2\right)\left(2s^2-2s+1\right)$ .

Calculation:

Steps in horizontal form method are:

• Separate the two binomials using multiplication sign.
• Multiply first binomial with each terms of second.
• Combine of add the like terms.

The given expression is solved as follows:

  $\begin{array}{l}\Rightarrow \left(3s+2\right)\left(2s^2-2s+1\right)\\ \Rightarrow \left(3s\right)\times \left(2s^2-2s+1\right)+2\times \left(2s^2-2s+1\right)\\ \Rightarrow 6s^3-6s^2+3s+4s^2-4s+2\\ \Rightarrow 6s^3-2s^2-s+2\end{array}$

Thus, the result of multiplication is $6s^3-2s^2-s+2$ .