Chapter 4.10, Problem 9P

To determine

To find: The three consecutive odd integers.

Answer to Problem 9P

The three integers are 11,13,15.

Explanation of Solution

Given information: The sum of three consecutive odd integers is 24 more than the greatest of the three integers.

Calculation:

Let the first odd integer as ‘ x’

The second odd integer is $x+2$

The greatest odd integer is $x+4$

Sum of these three integers is 24 more than the $x+4$

So, the equation is

  $x+x+2+x+4=24+x+4$

Combine like terms and solve for x .

  $3x+6=x+28$

Subtract both sides x

  $2x+6=28$

Subtract both sides 6.

  $2x=22$

Divide both sides by 2.

  $x=11$

So, second odd integer is $11+2=13$

Largest odd integer is $13+2=15$

Conclusion: The three odd integers are 11,13, 15.