Guided Proof Let S be a spanning set for a finite dimensional vector space V . Prove that there exists a subset S ′ of S that forms a basis for V . Getting Started: S is a spanning set, but it may not be a basis because it may be linearly dependent. You need to remove extra vectors so that a subset S ′ is a spanning set and is also linearly independent. (i) If S is linearly independent set, then you are done. If not, remove some vector v from S that is a linear combination of the other vectors in S . Call this set S 1 . (ii) If S 1 is a linearly independent set, then you are done. If not, then continue to remove dependent vectors until you produce a linearly independent subset S ′ . (iii) Conclude that this subset is the minimal spanning set S ′ .
Guided Proof Let S be a spanning set for a finite dimensional vector space V . Prove that there exists a subset S ′ of S that forms a basis for V . Getting Started: S is a spanning set, but it may not be a basis because it may be linearly dependent. You need to remove extra vectors so that a subset S ′ is a spanning set and is also linearly independent. (i) If S is linearly independent set, then you are done. If not, remove some vector v from S that is a linear combination of the other vectors in S . Call this set S 1 . (ii) If S 1 is a linearly independent set, then you are done. If not, then continue to remove dependent vectors until you produce a linearly independent subset S ′ . (iii) Conclude that this subset is the minimal spanning set S ′ .
Solution Summary: The author explains that the subset Sprime exists of set S which forms the basis for V.
Guided Proof Let
S
be a spanning set for a finite dimensional vector space
V
. Prove that there exists a subset
S
′
of
S
that forms a basis for
V
.
Getting Started:
S
is a spanning set, but it may not be a basis because it may be linearly dependent. You need to remove extra vectors so that a subset
S
′
is a spanning set and is also linearly independent.
(i) If
S
is linearly independent set, then you are done. If not, remove some vector
v
from
S
that is a linear combination of the other vectors in
S
. Call this set
S
1
.
(ii) If
S
1
is a linearly independent set, then you are done. If not, then continue to remove dependent vectors until you produce a linearly independent subset
S
′
.
(iii) Conclude that this subset is the minimal spanning set
S
′
.
Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.
Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution.
Remember that:
A matrix is in row echelon form if
Any row that consists only of zeros is at the bottom of the matrix.
The first non-zero entry in each other row is 1. This entry is called aleading 1.
The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.
PRIMERA EVALUACIÓN SUMATIVA
10. Determina la medida de los ángulos in-
teriores coloreados en cada poligono.
⚫ Octágono regular
A
11. Calcula es número de lados qu
poligono regular, si la medida
quiera de sus ángulos internos
• a=156°
A= (-2x+80
2
156 180-
360
0 = 24-360
360=24°
• a = 162°
1620-180-360
6=18-360
360=19
2=360=
18
12. Calcula las medida
ternos del cuadrilá
B
X+5
x+10
A
X+X+
Sx+6
5x=3
x=30
0
лаб
• Cuadrilátero
120°
110°
• α = 166° 40'
200=180-360
0 =
26-360
360=20
ひ=360
20
18 J
60°
⚫a=169° 42' 51.43"
169.4143180-340
0 = 10.29 54-360
360 10.2857
2=360
10.2857
@Sa
Please help I'm a working mom trying to help my son last minute (6th grader)! Need help with the blank ones and check the ones he got with full calculation so we can use it to study! Especially the mixed number fractions cause I'm rusty. Thanks in advance!
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