Chapter 4.5, Problem 56SR

To determine

To solve: the given equation

Answer to Problem 56SR

The required solution is $p=\frac{1}{3}$

Explanation of Solution

Given:

  $\frac{2}{3}+p=1$

Calculation:

Add both sides of equations with $-\frac{2}{3}$

  $\begin{array}{l}\frac{2}{3}+p-\frac{2}{3}=1-\frac{2}{3}\\ p=1-\frac{2}{3}\end{array}$

LCD is 3.Make the denominator 3

  $\begin{array}{l}p=\frac{1.3}{1.3}-\frac{2}{3}\\ p=\frac{3-2}{3}\\ p=\frac{1}{3}\end{array}$

Conclusion:

Hence, the solution is $p=\frac{1}{3}$ .