Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
9th Edition
ISBN: 9781305932302
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 45, Problem 47AP
To determine

The kinetic energy of the lithium nucleus.

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Use the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron). Neutron: m = 1.67493x10-27 kg = 1.008665 u = 939.57 MeV/c² . ¹H: mH = 1.67353x10-27 kg = 1.007825 u = 938.78 MeV/c² 1 1 u = 1.6605x10-27 kg = 931.5 MeV/c² . Consider the following decay: 239 Pu 235 U+ a. 239 Pu has a mass of 239.0521634 u, 235 U has a mass of 235.0439299 u, and a has a mass of 4.002603 u. 94 92 94 92 Determine the disintegration energy (Q-value) in MeV. Q = Determine the binding energy (in MeV) for 239 Pu. 94 EB =
Q4. a) Alpha decay is a two body final state process, in which a nucleus 4 AXz →(A−4) Y(z−2) +¹ He₂ + Qa If the masses of the atoms of the parent and the daughter nuclei are (roughly) Au, and (A — 4)u and that of the a particle is 4u, determine the relation between the kinetic energy To of the a particle and Qa. b) Explain why in case of even A nuclei, it is possible to have two most stable isobars, where as for odd A nuclei, there can be only one most stable isobar. c) Construct the mass parabolas for A = 101, and identify the most stable isobars. d) Construct the mass parabolas for A = 106, and identify the two most stable isobars.
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Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term

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