Explanation Given: Decibel reading of one sound is 6. Another sound has a decibel of 5. Approach: Decibel is a unit of Loudness of sound. The number of decibels is 10 times the logarithms of the relative intensity. decibels = 10 log ( relative intensity ) … ( 1 ) Calculation: Calculate the difference in decibel level. difference = 6 − 5 = 1 Let the relative intensity be x . The difference between the decibel level is 1, therefore the difference in logarithms is 1 10 = 0

Webassign Printed Access Card For Crauder/evans/noell's Functions And Change: A Modeling Approach To College Algebra, 6th Edition, Single-term

6th Edition

ISBN: 9781337652537

Author: Crauder, Bruce; Evans, Benny; Noell, Alan

Publisher: Cengage Learning

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Chapter 4.5, Problem 10SBE

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The way in which the relative intensities of two sounds compare.

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Webassign Printed Access Card For Crauder/evans/noell's Functions And Change: A Modeling Approach To College Algebra, 6th Edition, Single-term

Ch. 4.1 - TEST YOUR UNDESTANDING| FOR EXAMPLE 4.1...Ch. 4.1 - TEST YOUR UNDERSTANDING| FOR EXAMPLE 4.2 In a...Ch. 4.1 - Prob. 3TU Ch. 4.1 - Reminder Round all answers to two decimal places...Ch. 4.1 - Reminder Round all answers to two decimal places...Ch. 4.1 - Reminder Round all answers to two decimal places...Ch. 4.1 - Reminder Round all answers to two decimal places...Ch. 4.1 - Reminder Round all answers to two decimal places...Ch. 4.1 - Reminder Round all answers to two decimal places...Ch. 4.1 - Reminder Round all answers to two decimal places...

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The way in which the relative intensities of two sounds compare.

Solution Summary: The author explains how the relative intensities of two sounds compare. The number of decibels is 10 times the logarithms of relative intensity.

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Chapter 4 Solutions

To find:

The way in which the relative intensities of two sounds compare.