Logical “&&” Operator: Logical operator combines the results of one or more conditions. The logical “&&” is used to evaluate two expressions in order to obtain a single relational result. It returns the Boolean value “True” when both the operands are true, otherwise returns “False”. The first operand is evaluated first and all the side effects are completed before evaluating the logical “and” expression. The second operand is evaluated only if the first operand is “True”. Syntax for “&&” operator: The syntax for “&&” operator is given below: expression1 && expression2 Logical “||” Operator: Logical operator combines the results of one or more conditions. The logical “||” is used to evaluate two expressions in order to obtain a single relational result. It returns the Boolean value “True” when one of the operands is “True”. It returns “False” only if both the operands are “False”. The first operand is evaluated and all the effects are completed before it continues to evaluate the logical “||” expression. The second operand is evaluated only if the first operands return “False”. Syntax for “||” operator: The syntax for “||” operator is given below: Expression1 || expression2 Logical “!” Operator: Logical NOT operator one conditions. The logical “!” is used to evaluate one expressions in order to obtain a single relational result. It returns the Boolean value “True”. If the operand is “False”. It returns the Boolean value “False”. If the operand is “True”. Syntax for “!” operator: The syntax for “!” operator is given below: !Expression2

Question

Want to see the full answer?

Answer 1

Question

Chapter 4.4, Problem 4.13CP

Program Plan Intro

Logical “&&” Operator:

Logical operator combines the results of one or more conditions.

The logical “&&” is used to evaluate two expressions in order to obtain a single relational result.

It returns the Boolean value “True” when both the operands are true, otherwise returns “False”.

The first operand is evaluated first and all the side effects are completed before evaluating the logical “and” expression.

The second operand is evaluated only if the first operand is “True”.

Syntax for “&&” operator:

The syntax for “&&” operator is given below:

expression1 && expression2

Logical “||” Operator:

Logical operator combines the results of one or more conditions.

The logical “||” is used to evaluate two expressions in order to obtain a single relational result.

It returns the Boolean value “True” when one of the operands is “True”. It returns “False” only if both the operands are “False”.

The first operand is evaluated and all the effects are completed before it continues to evaluate the logical “||” expression.

The second operand is evaluated only if the first operands return “False”.

Syntax for “||” operator:

The syntax for “||” operator is given below:

Expression1 || expression2

Logical “!” Operator:

Logical NOT operator one conditions.

The logical “!” is used to evaluate one expressions in order to obtain a single relational result.

It returns the Boolean value “True”. If the operand is “False”.

It returns the Boolean value “False”. If the operand is “True”.

Syntax for “!” operator:

The syntax for “!” operator is given below:

!Expression2

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

After playing our giving implementation, your task is to implement Dinning Philosophers with semaphore in C, by including and Your implementation will require creating five philosophers, each identified by a number 0.4. Each philosopher will run as a separate thread. Create threads using Pthreads as discussed in the Lecture slides on Chapter 4 and Practice Lab on Threads. Your solution needs to accomplish the following: Implement in C (15 points) 1. dp1.c - You are to provide your solution to this assignment as a single C program named 'dp1.c using semaphore. Explain in you code (as comments) that the dead lock will happen or not. If there is a possible deadlock, you can simply solve the deadlock by pick the fork in order like the first solution in our slides. Solve Deadlock by Footman (15 points) 1. Here is a new solution to overcome the deadlock. The Dining Philosophers decide to hire a footman whose task to allow only four philosophers to sit on the table. When entering and…

8.4 Self-Bias Configuration 20. Determine Zi. Zo. and A,, for the network of Fig. 8.73 if gf, = 3000 μS and gos = 50 μs. 21. Determine Z, Zo, and A, for the network of Fig. 8.73 if the 20-uF capacitor is removed and the parameters of the network are the same as in Problem 20. Compare results with those of Problem 20. +12 V 3.3 ΚΩ HE C₂ Vo Z Zo C₁ 10 ΜΩ Z₁ 1.1 ΚΩ Cs 20 µF FIG. 8.73 Problems 20, 21, 22, and 59.

21. Determine Zi, Zo, and A, for the network of Fig. 8.73 if the 20-μF capacitor is removed and the parameters of the network are the same as in Problem 20. Compare results with those of Problem 20. +12 V 3.3 ΚΩ +6 C₂ C₁ Z₁ 10 ΜΩ 1.1 ΚΩ Cs 20 μF FIG. 8.73 Zo