Let p be prime and G the multiplicative group of units U p = { [ a ] ∈ Z p | [ a ] ≠ [ 0 ] } . Use Lagrange’s Theorem in G to prove Fermat’s Little Theorem in the form [ a ] p = [ a ] for any a ∈ Z . (compare with Exercise 54 in section 2.5) Let p be a prime integer. Prove Fermat’s Little Theorem: For any positive integer a , a p ≡ a ( mod p ) . (Hint: Use induction on a , with p held fixed.)
Let p be prime and G the multiplicative group of units U p = { [ a ] ∈ Z p | [ a ] ≠ [ 0 ] } . Use Lagrange’s Theorem in G to prove Fermat’s Little Theorem in the form [ a ] p = [ a ] for any a ∈ Z . (compare with Exercise 54 in section 2.5) Let p be a prime integer. Prove Fermat’s Little Theorem: For any positive integer a , a p ≡ a ( mod p ) . (Hint: Use induction on a , with p held fixed.)
Solution Summary: The author explains Fermat's Little Theorem in the form of [a]p=[A] by using Lagrange'
Let
p
be prime and
G
the multiplicative group of units
U
p
=
{
[
a
]
∈
Z
p
|
[
a
]
≠
[
0
]
}
. Use Lagrange’s Theorem in
G
to prove Fermat’s Little Theorem in the form
[
a
]
p
=
[
a
]
for any
a
∈
Z
. (compare with Exercise 54 in section 2.5)
Let
p
be a prime integer. Prove Fermat’s Little Theorem: For any positive integer
a
,
a
p
≡
a
(
mod
p
)
. (Hint: Use induction on
a
, with
p
held fixed.)
I want to learn this topic l dont know anything about it
Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution.
Remember that:
A matrix is in row echelon form if
Any row that consists only of zeros is at the bottom of the matrix.
The first non-zero entry in each other row is 1. This entry is called aleading 1.
The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.
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