BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
10th Edition
ISBN: 9781305967359
Author: STARR
Publisher: CENGAGE L
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Chapter 44, Problem 11SA
Summary Introduction
Introduction:
"Biodiversity" refers to the variety of species on Earth. Species richness is the common measure of a region's biodiversity.
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- 2 A linear fragment of DNA containing the Insulin receptor gene is shown below, where boxes represent exons and lines represent introns. Assume transcription initiates at the leftmost EcoRI site. Sizes in kb are indicated below each segment. Vertical arrows indicate restriction enzyme recognition sites for Xbal and EcoRI in the Insulin receptor gene. Horizontal arrows indicate positions of forward and reverse PCR primers. The Horizontal line indicates sequences in probe A. Probe A EcoRI Xbal t + XbaI + 0.5kb | 0.5 kb | 0.5 kb | 0.5kb | 0.5 kb | 0.5 kb | 1.0 kb EcoRI On the gel below, indicate the patterns of bands expected for each DNA sample Lane 1: EcoRI digest of the insulin receptor gene Lane 2: EcoRI + Xbal digest of the insulin receptor gene Lane 3: Southern blot of the EcoRI + Xbal digest insulin receptor gene probed with probe A Lane 4: PCR of the insulin receptor cDNA using the primers indicated Markers 6 5 4 1 0.5 1 2 3 4arrow_forward4. (10 points) woman. If both disease traits are X-linked recessive what is the probability A man hemizygous for both hemophilia A and color blindness mates with a normal hemophilia A nor colorblindness if the two disease genes show complete that a mating between their children will produce a grandson with neither a. linkage? (5 points) that a mating between their children will produce a grandson with both hemophilia A and colorblindness if the two disease genes map 40 cM apart? (5 points)arrow_forward2 2 1.5 1.0 0.67 5. (15 points) An individual comes into your clinic with a phenotype that resembles Down's syndrome. You perform CGH by labeling the patient's hobe DNA red and her mother's DNA green. Plot the expected results of the Red:Green ratio if: A. The cause of the syndrome was an inversion on one chromosome 21 in the child 0.5 1.5 1.0 0.67 0.5 21 p 12345678910 CEN q 123456789 10 11 12 13 14 15 16 17 18 19 B. The cause of the syndrome was a duplication of the material between 21q14 and 21q18 on one chromosome in the child 21 p 123456789 10 CEN q 12345678910 11 12 13 14 15 16 17 18 19 C. The mother carried a balanced translocation that segregated by adjacent segregation in meiosis I and resulted in a duplication in the child of the material distal to the translocation breakpoint at 21q14. 1.5 1.0 0.67 0.5 21 p 12345678910 CEN q 123456789 10 11 12 13 14 15 16 17 18 19 mom seal bloarrow_forward
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