Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
9th Edition
ISBN: 9781305372337
Author: Raymond A. Serway | John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 43, Problem 49P
To determine
The magnitude of the current in the diode when the battery is reversed.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A pn junction diode and a Schottky diode have equal cross-sectional areas and have forward-bias currents of 0.5 mA. The reverse-saturation current of the Schottky diode is The difference in forward-bias voltages between the two diodes is 0.30 V. Determine the reverse-saturation current of the pn junction diode.
What fraction of the electrons in a good conductor have energies between 0.90 EF and EF at T = 0?
A diode is an electronic device that let the current flow in only one direction, that is the current
through the diode is I=V/R (R is the diode resistance, a constant) if V > 0 and I=0 if V≤0. The
diode is excited by an alternative voltage V(t) = cos(wot).
(a) Sketch the diode response I(t) as a function of t. Indicate clearly the minimum values +to
for which I(t) drops to zero.
(b) Calculate the Fourier transform F(w) of the diode response. Hint: because the function is
periodic, you only have to calculate the integral between ±to.
(c) Schematically plot F(w) versus w.
(d) A Lock-in amplifier is an electronic setup that can measure the response at integer
frequency of the excitation frequency. What would a Lock-in measure at f = 2fo?
(wo = 2nfo).
Chapter 43 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
Ch. 43.1 - For each of the following atoms or molecules,...Ch. 43.2 - Prob. 43.2QQCh. 43.2 - Prob. 43.3QQCh. 43 - Prob. 1OQCh. 43 - Prob. 2OQCh. 43 - Prob. 3OQCh. 43 - Prob. 4OQCh. 43 - Prob. 5OQCh. 43 - Prob. 6OQCh. 43 - Prob. 7OQ
Ch. 43 - Prob. 1CQCh. 43 - Prob. 2CQCh. 43 - Prob. 3CQCh. 43 - Prob. 4CQCh. 43 - Prob. 5CQCh. 43 - Prob. 6CQCh. 43 - Prob. 7CQCh. 43 - Prob. 8CQCh. 43 - Discuss models for the different types of bonds...Ch. 43 - Prob. 10CQCh. 43 - Prob. 1PCh. 43 - Prob. 2PCh. 43 - Prob. 3PCh. 43 - Prob. 4PCh. 43 - Prob. 5PCh. 43 - Prob. 6PCh. 43 - Prob. 7PCh. 43 - Prob. 8PCh. 43 - Prob. 9PCh. 43 - Prob. 10PCh. 43 - Prob. 12PCh. 43 - Prob. 13PCh. 43 - Prob. 14PCh. 43 - Prob. 15PCh. 43 - Prob. 16PCh. 43 - The nuclei of the O2 molecule are separated by a...Ch. 43 - Prob. 18PCh. 43 - Prob. 19PCh. 43 - Prob. 20PCh. 43 - Prob. 21PCh. 43 - Prob. 22PCh. 43 - Prob. 23PCh. 43 - Prob. 24PCh. 43 - Prob. 25PCh. 43 - Prob. 27PCh. 43 - Prob. 28PCh. 43 - Prob. 29PCh. 43 - Prob. 30PCh. 43 - Prob. 31PCh. 43 - Prob. 32PCh. 43 - Prob. 33PCh. 43 - Prob. 34PCh. 43 - Prob. 35PCh. 43 - Prob. 36PCh. 43 - Prob. 37PCh. 43 - Prob. 38PCh. 43 - Prob. 39PCh. 43 - Prob. 40PCh. 43 - Prob. 41PCh. 43 - Prob. 42PCh. 43 - Prob. 43PCh. 43 - Prob. 44PCh. 43 - Prob. 45PCh. 43 - Prob. 46PCh. 43 - Prob. 47PCh. 43 - Prob. 49PCh. 43 - Prob. 50PCh. 43 - Prob. 51PCh. 43 - A direct and relatively simple demonstration of...Ch. 43 - Prob. 53PCh. 43 - Prob. 54APCh. 43 - Prob. 55APCh. 43 - Prob. 56APCh. 43 - Prob. 57APCh. 43 - Prob. 58APCh. 43 - Prob. 59APCh. 43 - Prob. 61APCh. 43 - Prob. 62APCh. 43 - Prob. 63CPCh. 43 - As an alternative to Equation 43.1, another useful...
Knowledge Booster
Similar questions
- A diode is an electronic component through which an electric current flows according to the potential difference applied across its terminals. The figure to the side shows the typical curve of a diode. At what point on the curve is the resistance of the diode minimum? At what point is it maximum? Justify your answer.arrow_forwardThe number of silicon atoms per m3 is 5 × 1028. This is doped simultaneously with 5 × 1022 atoms per m3 of Arsenic and 5 × 1020 per m3 atoms of Indium. Calculate the number of electrons and holes.arrow_forwardA conductive wire has a conductivity of ( 0.649 × 10^-8) at room temperature are ( 5.8 x 1028) conduction electron/m.calculate the mobility,resistivity and relaxation time of electronsarrow_forward
- A high electron mobility transistor (HEMT) controls large currents by applying a small voltage to a thin sheet of electrons. The density and mobility of the electrons in the sheet are critical for the operation of the HEMT. HEMTS consisting of AlGaN/GaN/Si are being studied because they promise better performance at higher powers, temperatures, and frequencies than conventional silicon HEMTS can achieve. In one study, the Hall effect was used to measure the density of electrons in one of these new HEMTs. When a current of 12.1 ?A flows through the length of the electron sheet, which is 1.12 mm long, 0.223 mm wide, and 15.1 nm thick, a magnetic field of 1.05 T perpendicular to the sheet produces a voltage of 0.511 mV across the width of the sheet. What is the density of electrons per m3 in the sheet?arrow_forwardGiven the resistivity of sodium 4.2 x10 Q2.m and the relaxation time 3.1x10-14 S, calculate the number of free electrons per cm³ and per atom.arrow_forwardThe Electronic Current through an electronic device is due to the flow of both electrons and holes. Through a certain cross section of the device 4 * 10^15 electrons and 3 * 10^15 holes flow per second in opposite directions. The total current through the device is ________ * 10^-3 Amperearrow_forward
- If the diode for the given circuit below is a Silicon diode, how much is the maximum positive voltage (taken at the series connection of the diode and the battery)? R1 1 V1 1kQ D1 7.5V Vout 1kHz 4 0° V2 I 3.6V Answer:arrow_forwardA germanium diode is used to detect radiation with energy of 1.6 MeV. To do so, the anode (positive terminal) is exposed to the incoming radiation. Assume that the energy is absorbed entirely at the point of entry or the anode. With mobilities of 1,150 cm?/V.s for holes and 3,750 cm?/V.s for electrons, calculate the current through the diode with reverse bias: V = 24 V and d = 12 mm. Neglect the effects of electrodes and 4. of the n and p layers and assume a single radiation event, that is a single particle or a short burst of radiation. (Charge of an electron = 1.602 x 10-19 C; d is the distance between anode and cathode).arrow_forwardAn AL wire with an atomic mass of 26.98 g/mole with a cross sectional area of 4 x 10-6 /m2 carries a 5Acurrent. Find the drift velocity of the electrons in m/s through the wire, assuming that each Al atomcontributes an electron. The density of Al is 2.7 g/cm3.arrow_forward
- 1 A bar of n-type germanium 10mmx1mmx1mm. The electron density in the bar is 7×10²1 m³ and B=0.2 Wb/m². If one millivolt is applied across the long ends of the bar, determine the current through the bar, the Hall coefficient and the Hall voltage. Assume n = 0.39 m²/v.s. Ans: 43.6 μA; 8.9×10-4 m³/C; 7.76 μV.arrow_forwardIn a Si semiconductor sample of 200 am length at 600 K the hole concentration as a' function of the sample length follows a quadratic relation of the form p (x) = 1 x1015x, at equilibrium the value of the electric field at 160 jum will be: O 1.935 V/cm O 3.250 V/cm O 5805 V/cm O 55.56 V/cm O 6.450 V/cmarrow_forwardThe induced electron flow in Situation A would be ___.The induced electron flow in SItuation B would be ____.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning