Explanation Given information: S − 5 p w = 3 p w 2 − 6 p q and p and q are positive constants. Formula used: If f ( x ) = a x 2 + b x + c , its extreme is at x = − b 2 a . Calculation: S − 5 p w = 3 p w 2 − 6 p q (Given) ⇒ S = 3 p w 2 + 5 p w − 6 p q By the formula that if f ( x ) = a x 2 + b x + c , its extreme is at x = − b 2 a , we have for the above equation w = − 5 p 2 ( 3 q ) w = − 5 p 6 q Then to find the minimum value w = − 5 p 6 q

6th Edition

ISBN: 9781119275565

Author: Hughes-Hallett

Publisher: WILEY

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Domain

In simple mathematics terms, a domain is defined as the space on which all the possible inputs for the function will lie. It can also be expressed as a set of departures for the required function.

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Chapter 4.3, Problem 47P

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To find:

The value of w minimizes S if S−5pw=3pw2−6pq and p and q are positive constants.

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Chapter 4.3, Problem 46P

Chapter 4.3, Problem 48P

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Chapter 4 Solutions

APPLIED CALCULUS-PRINT COMPANION (LL)

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The value of w minimizes S if S − 5 p w = 3 p w 2 − 6 p q and p and q are positive constants.

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To find: The value of w minimizes S if S−5pw=3pw2−6pq and p and q are positive constants.

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Chapter 4 Solutions

To find:

The value of w minimizes S if S−5pw=3pw2−6pq and p and q are positive constants.