Explanation Given information: f ( x ) = 2 e x + 3 e − x . The domain is the real values. Fact used: If f ' changes from negative to positive at p, then f has a local minimum at p. If f ' changes from positive to negative at p, then f has a local maximum at p. Calculation: f ( x ) = 2 e x + 3 e − x (Given) Differentiating with respect to ‘x’, we get f ' ( x ) = 2 e x − 3 e − x Equating f ' ( x ) = 0 ⇒ 2 e x − 3 e − x = 0 ⇒ 2 e 2 x − 3 e x = 0

6th Edition

ISBN: 9781119275565

Author: Hughes-Hallett

Publisher: WILEY

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Question

Chapter 4.3, Problem 42P

To determine

To find:

The exact global maximum and minimum values of the function f(x)=2ex+3e−x.

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Chapter 4.3, Problem 41P

Chapter 4.3, Problem 43P

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Chapter 4 Solutions

APPLIED CALCULUS-PRINT COMPANION (LL)

Ch. 4.1 - Prob. 1P Ch. 4.1 - Prob. 2P Ch. 4.1 - Prob. 3P Ch. 4.1 - Prob. 4P Ch. 4.1 - Prob. 5P Ch. 4.1 - Prob. 6P Ch. 4.1 - Prob. 7P Ch. 4.1 - Prob. 8P Ch. 4.1 - Prob. 9P Ch. 4.1 - Prob. 10P

Ch. 4.1 - Prob. 11P Ch. 4.1 - Prob. 12P Ch. 4.1 - Prob. 13P Ch. 4.1 - Prob. 14P Ch. 4.1 - Prob. 15P Ch. 4.1 - Prob. 16P Ch. 4.1 - Prob. 17P Ch. 4.1 - Prob. 18P Ch. 4.1 - Prob. 19P Ch. 4.1 - Prob. 20P Ch. 4.1 - Prob. 21P Ch. 4.1 - Prob. 22P Ch. 4.1 - Prob. 23P Ch. 4.1 - Prob. 24P Ch. 4.1 - Prob. 25P Ch. 4.1 - Prob. 26P Ch. 4.1 - Prob. 27P Ch. 4.1 - Prob. 28P Ch. 4.1 - Prob. 29P Ch. 4.1 - Prob. 30P Ch. 4.1 - Prob. 31P Ch. 4.1 - Prob. 32P Ch. 4.1 - Prob. 33P Ch. 4.1 - Prob. 34P Ch. 4.1 - Prob. 35P Ch. 4.1 - Prob. 36P Ch. 4.1 - Prob. 37P Ch. 4.1 - Prob. 38P Ch. 4.1 - Prob. 39P Ch. 4.1 - Prob. 40P Ch. 4.1 - Prob. 41P Ch. 4.1 - Prob. 42P Ch. 4.1 - Prob. 43P Ch. 4.1 - Prob. 44P Ch. 4.1 - Prob. 45P Ch. 4.1 - Prob. 46P Ch. 4.1 - Prob. 47P Ch. 4.1 - Prob. 48P Ch. 4.1 - Prob. 49P Ch. 4.1 - Prob. 50P Ch. 4.1 - Prob. 51P Ch. 4.1 - Prob. 52P Ch. 4.1 - Prob. 53P Ch. 4.1 - Prob. 54P Ch. 4.1 - Prob. 55P Ch. 4.1 - Prob. 56P Ch. 4.1 - Prob. 57P Ch. 4.1 - Prob. 58P Ch. 4.2 - Prob. 1P Ch. 4.2 - Prob. 2P Ch. 4.2 - 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Knowledge Booster

The exact global maximum and minimum values of the function f ( x ) = 2 e x + 3 e − x .

Solution Summary: The author calculates the global minimum and minimum values of the function f(x)=2ex+3

To find:

The exact global maximum and minimum values of the function f(x)=2ex+3e−x.

Want to see the full answer?

Chapter 4 Solutions

The exact global maximum and minimum values of the function f ( x ) = 2 e x + 3 e − x .

Solution Summary: The author calculates the global minimum and minimum values of the function f(x)=2ex+3

To find: The exact global maximum and minimum values of the function f(x)=2ex+3e−x.

Want to see the full answer?

Chapter 4 Solutions

To find:

The exact global maximum and minimum values of the function f(x)=2ex+3e−x.