MASTERINGPHYSICS W/ETEXT ACCESS CODE 6
13th Edition
ISBN: 9781269542661
Author: YOUNG
Publisher: PEARSON C
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Question
Chapter 43, Problem 43.49P
(a)
To determine
The minimum energy required to remove one neutron from the nucleus
(b)
To determine
The binding energy per nucleon for
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(a) For the nuclei B and C, determine the difference in binding energy per nucleon (in MeV). (Let the mass of a proton be 1.0078 u, the mass of a neutron be 1.0087 u, the mass of ¹B be 11.0093 u, and the mass of C be 11.0114 u.)
0.0762
x
Review the meaning of the A, Z and N numbers. Review how to find the binding energy of a nucleus and then the binding energy per nucleon. MeV
(b) This difference in binding energy is due to which of the following?
O Greater electron attraction for the C atom
O Greater electron repulsion for the
C atom
Ⓒ Greater neutron attraction for the
C nucleus
O Greater neutron repulsion for the ¹C nucleus
O Greater proton attraction for the C nucleus
Ⓒ Greater proton repulsion for the C nucleus
(b) What is the Q value of the reaction? (The atomic mass of
7
3
Li
is 7.016004 u, the atomic mass of
4
2
He
is 4.002603 u, the atomic mass of a neutron is 1.008665 u, and the atomic mass of the unknown product is 10.012937 u.)
The half-life of 27Mg is 9.50 min. initially there were 3.70× 1012 27Mg nuclei present. How many 27Mg nuclei are left 29.0 min later? Please give your answer to 2 significant figures.
Calculate the 27Mg activities (in Ci) at t = 0 and t = 29.0 min.
Chapter 43 Solutions
MASTERINGPHYSICS W/ETEXT ACCESS CODE 6
Ch. 43.1 - Prob. 43.1TYUCh. 43.2 - Rank the following nuclei in order from largest to...Ch. 43.3 - Prob. 43.3TYUCh. 43.4 - Prob. 43.4TYUCh. 43.5 - Prob. 43.5TYUCh. 43.6 - Prob. 43.6TYUCh. 43.7 - Prob. 43.7TYUCh. 43.8 - Prob. 43.8TYUCh. 43 - Prob. 43.1DQCh. 43 - Prob. 43.2DQ
Ch. 43 - Prob. 43.3DQCh. 43 - Prob. 43.4DQCh. 43 - Prob. 43.5DQCh. 43 - Prob. 43.6DQCh. 43 - Prob. 43.7DQCh. 43 - Prob. 43.8DQCh. 43 - Prob. 43.9DQCh. 43 - Prob. 43.10DQCh. 43 - Prob. 43.11DQCh. 43 - Prob. 43.12DQCh. 43 - Prob. 43.13DQCh. 43 - Prob. 43.14DQCh. 43 - Prob. 43.15DQCh. 43 - Prob. 43.16DQCh. 43 - Prob. 43.17DQCh. 43 - The most common radium isotope found on earth,...Ch. 43 - Prob. 43.19DQCh. 43 - Prob. 43.20DQCh. 43 - Prob. 43.1ECh. 43 - Prob. 43.2ECh. 43 - Prob. 43.3ECh. 43 - Prob. 43.4ECh. 43 - Prob. 43.5ECh. 43 - Prob. 43.6ECh. 43 - Prob. 43.7ECh. 43 - Prob. 43.8ECh. 43 - Prob. 43.9ECh. 43 - Prob. 43.10ECh. 43 - Prob. 43.11ECh. 43 - Prob. 43.12ECh. 43 - Prob. 43.13ECh. 43 - Prob. 43.14ECh. 43 - Prob. 43.15ECh. 43 - Prob. 43.16ECh. 43 - Prob. 43.17ECh. 43 - Prob. 43.18ECh. 43 - Prob. 43.19ECh. 43 - Prob. 43.20ECh. 43 - Prob. 43.21ECh. 43 - Prob. 43.22ECh. 43 - Prob. 43.23ECh. 43 - Prob. 43.24ECh. 43 - Prob. 43.25ECh. 43 - Prob. 43.26ECh. 43 - Measurements on a certain isotope tell you that...Ch. 43 - Prob. 43.28ECh. 43 - Prob. 43.29ECh. 43 - Prob. 43.30ECh. 43 - Prob. 43.31ECh. 43 - Prob. 43.32ECh. 43 - Prob. 43.33ECh. 43 - Prob. 43.34ECh. 43 - Prob. 43.35ECh. 43 - Prob. 43.36ECh. 43 - Prob. 43.37ECh. 43 - Prob. 43.38ECh. 43 - Prob. 43.39ECh. 43 - Prob. 43.40ECh. 43 - Prob. 43.41ECh. 43 - Energy from Nuclear Fusion. Calculate the energy...Ch. 43 - Prob. 43.43ECh. 43 - Prob. 43.44ECh. 43 - Prob. 43.45ECh. 43 - Prob. 43.46ECh. 43 - Prob. 43.47PCh. 43 - Prob. 43.48PCh. 43 - Prob. 43.49PCh. 43 - Prob. 43.50PCh. 43 - Prob. 43.51PCh. 43 - Prob. 43.52PCh. 43 - Prob. 43.53PCh. 43 - Prob. 43.54PCh. 43 - Prob. 43.55PCh. 43 - Prob. 43.56PCh. 43 - Prob. 43.57PCh. 43 - Prob. 43.58PCh. 43 - Prob. 43.59PCh. 43 - Prob. 43.60PCh. 43 - Prob. 43.61PCh. 43 - Prob. 43.62PCh. 43 - Prob. 43.63PCh. 43 - Prob. 43.64PCh. 43 - Prob. 43.65PCh. 43 - Prob. 43.66PCh. 43 - Prob. 43.67PCh. 43 - Prob. 43.68PCh. 43 - DATA Your company develops radioactive isotopes...Ch. 43 - Prob. 43.70PCh. 43 - Prob. 43.71CPCh. 43 - Prob. 43.72CPCh. 43 - Prob. 43.73PPCh. 43 - Prob. 43.74PPCh. 43 - Prob. 43.75PPCh. 43 - Prob. 43.76PPCh. 43 - Prob. 43.77PP
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- No stable nuclides exist that have Z greater than ___. (10.3)arrow_forwardIn a 3109 yearold rock that originally contained some 238U, which has a halflife of 4.5109 years, we expect to find some 238U remaining in it. Why are 226Ra, 222Rn, and 210Po also found in such a rock, even though they have much shorter halflives (1600 years, 3.8 days, and 133 days, respectively)?arrow_forwardData from the appendices and the periodic table may be needed for these problems. Show that the activity of the 14C in 1.00 g of 12C found in living tissue is 0.250 Bq.arrow_forward
- If air is 80% N15 and 20% O16. Using the data below, calculate the average distance a thermal neutron travels in air before having an interaction. Air density = 1.202 gm/cm3 %3D o16 atomic wt 15.994 gm N15 atomic wt = 14.0067 gm %3! N15 total microscopic cross 016 total microscopic cross section = 4.03 b 12.20 b %3D section %3D 129.328 cm 1.855 cm 123.762 cm 12.653 cmarrow_forwardB) Calculate the average nuclear binding energy of 13Al nucleus, knowing that the mass defect of aluminum = 0.24136 a.m.u. , then state whether the nucleus of 7Al is stable or not. (1 a.m.u. = 1.6605 x 10-27 kg, 1 m.e.v. = 1.602177 x 10-13 Jules).arrow_forwardMany transuranium elements, such as neptunium-240, have very short half-lives. (For 240 Np, the half-life is 62 minutes.) However, some, like uranium-233 (half-life is 1.59 x 10° years), have relatively long half-lives. Use the masses given in the following table to calculate the change in energy when 1 mole of 240 Np nuclei and I mole of 23U nuclei are each formed from their respective number of protons and neutrons. Atom or Particle Atomic Mass Neutron 1.67493 x 10-24 g Proton 1.67262 x 10-24 g Electron 9.10939 x 10-28 240 Np 3.98623 x 102 233 U 3.86972 x 10 2"g (Since the masses of 240 Np and 23 U are atomic masses, they each include the mass of the electrons present. The mass of the nucleus will be the atomic mass minus the mass of the electrons.) 240 Submit Answer Try Another Version 9 item attempts remainingarrow_forward
- Help with d e and farrow_forwardA radioactive sample contains 3.50 μg of pure 11 C, which has a half-life of 20.4 min. (a) How many moles of 11C are present initially? (b) Determine the number of nuclei present initially. What is the activity of the sample (c) initially and (d) after 8.00 h?arrow_forwardA sample of shale contains 0.055% 238U by weight. Calculate the number of spontaneous fi ssions in one day in a 106-kg pile of the shale by determining (a) the mass of 238U present, (b) the number of 238U atoms, (c) the fi ssion activity, and fi nally (d) the number of fi ssions. The spontaneous fi ssion activity rate of 238U is 6.7 fi ssions/kg*s.arrow_forward
- The liquid drop model may be used to determine the nuclear binding energy for an isotope. This model uses the semiempirical binding energy formula, which takes into consideration four major effects (one term per effect) that contribute to the nuclear binding energy. The semiempirical binding energy formula may be expressed as: Z(Z - 1) C3 A1/3 (N – z)2 E, = C;A – C,A?/3 A The first term is the volume term, the second is the surface term, the third is the Coulomb term, and the fourth is the symmetry term. For nuclei having A 2 15, the constants have the following values: = 15.7 MeV, C, = 17.8 MeV, C3 = 0.71 MeV, and C. = 23.6 MeV 56 (a) Use the semiempirical binding energy formula to determine the nuclear binding energy (in MeV) for the isotope Fe. 26 MeV (b) Determine the percentage contribution to the binding energy by each of the four terms. (You should expect positive and negative values, but the sum should be 100%. Due to the nature of this problem, do not use rounded intermediate…arrow_forward(Answer in MeV) Question in imagearrow_forward56Fe is among the most tightly bound of all nuclides. It makes up more than 90% of natural iron. Note that 56Fe has an even number of both protons and neutrons. Calculate BE/A, the binding energy per nucleon, for 56Fe in megaelectron volts per nucleon.arrow_forward
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