Biology
Biology
5th Edition
ISBN: 9781260487947
Author: BROOKER
Publisher: MCG
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Chapter 4.3, Problem 2CS
Summary Introduction

To explain:  The relation between the shapes of structures involved in the gas exchange and the surface area/volume ratio.

Introduction:  Living organisms consist of cells and almost all cells are small in size. The large sized organisms have more number of cells instead of having larger cells. Cells are small in size so that the amount of nutrient uptake and waste export through the plasma membrane can be decreased. A cell should have an appropriate surface area to volume ration in order to sustain.

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After you feel comfortable with your counting method and identifying cells in the various stages of mitosis, use the four images below of whitefish blastula to count the cells in each stage until you reach 100 total cells, recording your data below in Data Table 1. (You may not need to use all four images. Stop counting when you reach 100 total cells.) After totaling the cells in each stage, calculate the percent of cells in each stage. (Divide total of stage by overall total of 100 and then multiply by 100 to obtain percentage.)   Data Table 1Stage    Totals    PercentInterphase        Mitosis:        Prophase        Metaphase        Anaphase        Telophase        Cytokinesis        Totals    100    100% To find the length of time whitefish blastula cells spend in each stage, multiply the percent (recorded as a decimal, in other words take the percent number and divide by 100) by 24 hours. (Example: If percent is 20%, then Time in Hours = .2 * 24 = 4.8) Record your data in Data…
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