Chapter 4.3, Problem 1Q

To determine

To write: Equation of the line in slop-intercept form using given points on graph.

Answer to Problem 1Q

The equation of the line in slope-intercept form is $y=5x-2$ .

Explanation of Solution

Given information: Points are $(0,-2)$ and $(1,3)$ .

Calculation:

Slope intercept form: $y=mx+b$

  $m=\frac{y_2-y_1}{x_2-x_1}$

  $\begin{array}{l}m=\frac{3+2}{1-0}\\ m=5\end{array}$

Because the line crosses the $y-axis$ at $(0,-2)$ , $\therefore$ $y-\mathrm{int}ercept$ is $-2$ .

Substituting the values derived so far in slope intercept form,

  $y=5x-2$

Thus, the equation of the line in slope-intercept form is $y=5x-2$ .