Advertising: point of diminishing returns. A company estimates that it will sell N ( x ) units of a product after spending $ x thousand on advertising, as given by N ( x ) = − 0.5 x 4 + 46 x 3 − 1 , 080 x 2 + 160 , 000 24 ≤ x ≤ 45 When is the rate of change of sales increasing and when is it decreasing? What is the point of diminishing returns and the maximum rate of change of sales? Graph N and N ′ on the same coordinate system .
Advertising: point of diminishing returns. A company estimates that it will sell N ( x ) units of a product after spending $ x thousand on advertising, as given by N ( x ) = − 0.5 x 4 + 46 x 3 − 1 , 080 x 2 + 160 , 000 24 ≤ x ≤ 45 When is the rate of change of sales increasing and when is it decreasing? What is the point of diminishing returns and the maximum rate of change of sales? Graph N and N ′ on the same coordinate system .
Solution Summary: The author illustrates the intervals where the rate of change of function increases and decreases, as well as the diminishing returns and the maximum rate.
Advertising: point of diminishing returns. A company estimates that it will sell N(x) units of a product after spending $x thousand on advertising, as given by
N
(
x
)
=
−
0.5
x
4
+
46
x
3
−
1
,
080
x
2
+
160
,
000
24
≤
x
≤
45
When is the rate of change of sales increasing and when is it decreasing? What is the point of diminishing returns and the maximum rate of change of sales? Graph N and N′ on the same coordinate system.
System that uses coordinates to uniquely determine the position of points. The most common coordinate system is the Cartesian system, where points are given by distance along a horizontal x-axis and vertical y-axis from the origin. A polar coordinate system locates a point by its direction relative to a reference direction and its distance from a given point. In three dimensions, it leads to cylindrical and spherical coordinates.
Task number: A1.1, A1.7
Topic: Celestial Navigation, Compass - Magnetic and Gyro
Activ Determine compass error (magnetic and gyro) using azimuth choosing a suitable
celestial body (Sun/ Stars/ Planets/ Moon). Apply variation to find the deviation of the magnetic
compass.
Minimum number of times that activity should be recorded: 6 (2 each phase)
Sample calculation (Azimuth- Planets):
On 06th May 2006 at 22h20m 10s UTC, a vessel in position 48°00'N 050°00'E observed Mars bearing
327° by compass. Find the compass error. If variation was 4.0° East, calculate the deviation.
GHA Mars (06d 22h):
Increment (20m 10s):
089° 55.7'
005° 02.5'
v (0.9):
(+)
00.3'
GHA Mars:
094° 58.5'
Longitude (E):
(+) 050° 00.0' (plus- since longitude is easterly)
LHA Mars:
144° 58.5'
Declination (06d 22h):
d (0.2):
N 024° 18.6'
(-)
00.1'
Declination Mars:
N 024° 18.5'
P=144° 58.5' (If LHA<180°, P=LHA)
A Tan Latitude/ Tan P
A Tan 48° 00' Tan 144° 58.5'
A = 1.584646985 N (A is named opposite to latitude, except when…
Task number: A1.1, A1.7
Topic: Celestial Navigation, Compass - Magnetic and Gyro
Activ Determine compass error (magnetic and gyro) using azimuth choosing a suitable
celestial body (Sun/ Stars/ Planets/ Moon). Apply variation to find the deviation of the magnetic
compass.
Minimum number of times that activity should be recorded: 6 (2 each phase)
Sample calculation (Azimuth- Planets):
On 06th May 2006 at 22h20m 10s UTC, a vessel in position 48°00'N 050°00'E observed Mars bearing
327° by compass. Find the compass error. If variation was 4.0° East, calculate the deviation.
GHA Mars (06d 22h):
Increment (20m 10s):
089° 55.7'
005° 02.5'
v (0.9):
(+)
00.3'
GHA Mars:
094° 58.5'
Longitude (E):
(+) 050° 00.0' (plus- since longitude is easterly)
LHA Mars:
144° 58.5'
Declination (06d 22h):
d (0.2):
N 024° 18.6'
(-)
00.1'
Declination Mars:
N 024° 18.5'
P=144° 58.5' (If LHA<180°, P=LHA)
A Tan Latitude/ Tan P
A Tan 48° 00' Tan 144° 58.5'
A = 1.584646985 N (A is named opposite to latitude, except when…
Activ
Determine compass error using amplitude (Sun).
Minimum number of times that activity should be performed: 3 (1 each phase)
Sample calculation (Amplitude- Sun):
On 07th May 2006 at Sunset, a vessel in position 10°00'N 010°00'W observed the Sun bearing 288°
by compass. Find the compass error.
LMT Sunset:
LIT:
(+) 00d
07d 18h
00h
13m
40m
UTC Sunset:
07d
18h
53m
(added- since longitude is westerly)
Declination (07d 18h):
N 016° 55.5'
d (0.7):
(+)
00.6'
Declination Sun:
N 016° 56.1'
Sin Amplitude = Sin Declination/Cos Latitude
= Sin 016°56.1'/ Cos 10°00'
= 0.295780189
Amplitude=W17.2N
(The prefix of amplitude is named easterly if body is rising,
and westerly if body is setting. The suffix is named same
as declination)
True Bearing=287.2°
Compass Bearing= 288.0°
Compass Error = 0.8° West
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