Chapter 4.2, Problem 53AYU

The strain $S$ on a solid object depends on the external tension force $F$(in Newtons) acting on the solid and on the cross-sectional area $A$ (in m2) according to the model $S=5\times {10}^{-6}·\frac{F}{A}$ Find the strain for a rod with a cross-sectional area of $8.75\times {10}^{-3}{\text{m}}^{\text{2}}$ and a tension force of $2.45\times {10}^5\text{N}$.