Explanation Given: f ( x ) = 8 x 4 − 2 x 2 + 5 x − 1 and the interval is [ 0 , 1 ] Let a = 0 then a + 1 = 1 . The given f ( x ) = 8 x 4 − 2 x 2 + 5 x − 1 . Let us compute f ( 0 ) = 8 ( 0 ) − 2 ( 0 ) + 5 ( 0 ) − 1 = − 1 . f ( 1 ) = 8 − 2 + 5 − 1 = 10 Since f ( 0 ) and f ( 1 ) are of opposite signs, we need to find the midpoint of 0 and 1. The midpoint of 0 and 1 is 0.5 . Let m 1 = 0.5 . The f ( 0.5 ) = 8 ( 0.5 ) 4 − 2 ( 0.5 ) 2 + 5 ( 0...

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Chapter 4.6, Problem 118AYU

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To find: Use the bisection method to approximate the zero of $f (x) = 8 x^{4} - 2 x^{2} + 5 x - 1$ in the interval $[0, 1]$ correct to three decimal places. Verify your result using a graphing utility.

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Chapter 4.6, Problem 117AYU

Chapter 4.6, Problem 119AYU

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Use the bisection method to approximate the zero of f ( x ) = 8 x 4 − 2 x 2 + 5 x − 1 in the interval [ 0 , 1 ] correct to three decimal places. Verify your result using a graphing utility.

Solution Summary: The author explains the bisection method to approximate the zero of f ( x ) = 8 2 / 2 + 5 in the interval.

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To find: Use the bisection method to approximate the zero of $f (x) = 8 x^{4} - 2 x^{2} + 5 x - 1$ in the interval $[0, 1]$ correct to three decimal places. Verify your result using a graphing utility.

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Chapter 4 Solutions

Use the bisection method to approximate the zero of f ( x ) = 8 x 4 − 2 x 2 + 5 x − 1 in the interval [ 0 , 1 ] correct to three decimal places. Verify your result using a graphing utility.

Solution Summary: The author explains the bisection method to approximate the zero of f ( x ) = 8 2 / 2 + 5 in the interval.

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Videos

To find: Use the bisection method to approximate the zero of f( x ) = 8 x 4 − 2 x 2 + 5x − 1 in the interval [ 0, 1 ] correct to three decimal places. Verify your result using a graphing utility.

Want to see the full answer?

Chapter 4 Solutions

To find: Use the bisection method to approximate the zero of $f (x) = 8 x^{4} - 2 x^{2} + 5 x - 1$ in the interval $[0, 1]$ correct to three decimal places. Verify your result using a graphing utility.