Explanation Given, f ( x ) = ( x − 1 ) sin ( x ) -----------------------------------------------------------------------(1) Since function is product of polynomial and trigonometric functions therefore, function is continuous on [ 0 , 1 ] and differentiable on ( 0 , 1 ) . By inspection, one can see that f ( 0 ) = f ( 1 ) = 0 Now, from Mean Value Theorem There exist at least one x ∈

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topic…

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Chapter 4.2, Problem 52PS

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The proof that the equation tanx=1−x has at least one solution for 0<x<1 .

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Chapter 4.2, Problem 51PS

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Chapter 4 Solutions

Calculus

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The proof that the equation tan x = 1 − x has at least one solution for 0 < x < 1 .

Solution Summary: The author explains the proof that the equation mathrmtanx=1-x has at least one solution. Since function is product of polynomial and trigonometric functions, function

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The proof that the equation tanx=1−x has at least one solution for 0<x<1 .

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Chapter 4 Solutions

The proof that the equation tan x = 1 − x has at least one solution for 0 &lt; x &lt; 1 .

Solution Summary: The author explains the proof that the equation mathrmtanx=1-x has at least one solution. Since function is product of polynomial and trigonometric functions, function

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The proof that the equation tanx=1−x has at least one solution for 0<x<1 .

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Chapter 4 Solutions

The proof that the equation tan x = 1 − x has at least one solution for 0 < x < 1 .