Explanation Given : g ( u ) = sin u − cos u on [ 0 , π ] The given function, g ( u ) = sin u − cos u Now find derivative of g ( u ) g ' ( u ) = cos u + sin u For critical point, g ' ( u ) = 0 cos u + sin u = 0 tan u = − 1 u = 3 π 4 , 7 π 4 Critical point: x = 3 π 4 , 7 π 4 Now find double derivative g ' ' ( u ) = − sin u + cos u Now check double derivative for each critical value If double derivative is negative then maximum If double derivative is positive then minimum At u =

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 4.1, Problem 14PS

To determine

To find: The critical numbers of a function, g(u)=sinu−cosu on [0,π] and yields a minimum, maximum or neither.

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Chapter 4.1, Problem 13PS

Chapter 4.1, Problem 15PS

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Chapter 4 Solutions

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The critical numbers of a function, g ( u ) = sin u − cos u on [ 0 , π ] and yields a minimum, maximum or neither.

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To find: The critical numbers of a function, g(u)=sinu−cosu on [0,π] and yields a minimum, maximum or neither.

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Chapter 4 Solutions