Explanation Given : f ( x ) = 1 2 ( e x + e − x ) on [ 0 , 1 ] Concept Used: f ( x ) is a function that satisfies two condition: 1. f ( x ) is continuous on the closed interval [ a , b ] 2. f ( x ) is differentiable on the open interval ( a , b ) Then a number c must be lie between a and b, a < c < b f ' ( c ) = f ( b ) − f ( a ) b − a The given function, f ( x ) = 1 2 ( e x + e − x ) on [ 0 , 1 ] For MVT satisfy the function f ( x ) if 1. f ( x ) is continuous on the closed interval [ 0 , 1 ] 2

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 4.2, Problem 16PS

To determine

To find: The number c between the interval [0,1] which satisfy MVT of function f(x)=12(ex+e−x)

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Chapter 4.2, Problem 15PS

Chapter 4.2, Problem 17PS

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Chapter 4 Solutions

Calculus

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The number c between the interval [ 0 , 1 ] which satisfy MVT of function f ( x ) = 1 2 ( e x + e − x )

Solution Summary: The author explains that the function f(x) is a function that satisfies two conditions.

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To find: The number c between the interval [0,1] which satisfy MVT of function f(x)=12(ex+e−x)

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Chapter 4 Solutions