Consider the following two systems of equations: 5 x 1 + x 2 – 3 x 3 = 0 −9 x 1 + 2 x 2 + 5 x 3 = 1 4 x 1 + x 2 – 6 x 3 = 0 5 x 1 + x 2 – 3 x 3 = 0 −9 x 1 + 2 x 2 + 5 x 3 = 5 4 x 1 + x 2 – 6 x 3 = 45 It can be shown that the first system has a solution. Use this fact and the theory from this section to explain why the second system must also have a solution. (Make no row operations.)
Consider the following two systems of equations: 5 x 1 + x 2 – 3 x 3 = 0 −9 x 1 + 2 x 2 + 5 x 3 = 1 4 x 1 + x 2 – 6 x 3 = 0 5 x 1 + x 2 – 3 x 3 = 0 −9 x 1 + 2 x 2 + 5 x 3 = 5 4 x 1 + x 2 – 6 x 3 = 45 It can be shown that the first system has a solution. Use this fact and the theory from this section to explain why the second system must also have a solution. (Make no row operations.)
Solution Summary: The author explains the reason for two given system of equations that if the first system has a solution then the second system also has one.
It can be shown that the first system has a solution. Use this fact and the theory from this section to explain why the second system must also have a solution. (Make no row operations.)
Introductory and Intermediate Algebra for College Students (5th Edition)
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