Prescott's Microbiology
10th Edition
ISBN: 9781259281594
Author: Joanne Willey, Linda Sherwood Adjunt Professor Lecturer, Christopher J. Woolverton Professor
Publisher: McGraw-Hill Education
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Chapter 41.3, Problem 1MI
MICRO INQUIRY What foods are most prone to aflatoxin contamination?
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Chapter 41 Solutions
Prescott's Microbiology
Ch. 41.1 - What are some intrinsic factors that influence...Ch. 41.1 - How would the spoilage of bread differ from that...Ch. 41.1 - Why do sausage and other ground meat products...Ch. 41.1 - What extrinsic factors can determine whether food...Ch. 41.2 - MICRO INQUIRY Canned products such as vegetable...Ch. 41.2 - Describe the major approaches used in food...Ch. 41.2 - What types of chemicals can be used to preserve...Ch. 41.2 - What cellular component does HHP target? What is...Ch. 41.2 - How does nisin function? What bacterial genus...Ch. 41.2 - Prob. 5RIA
Ch. 41.2 - What are the major gases involved in MAP? How are...Ch. 41.3 - MICRO INQUIRY What foods are most prone to...Ch. 41.3 - What is the difference between a food-borne...Ch. 41.3 - What practical recommendations regarding food...Ch. 41.3 - Prob. 3RIACh. 41.3 - Members of what microbial genus produce fumonisins...Ch. 41.4 - MICRO INQUIRY Why is it important that PulseNet...Ch. 41.4 - How are most food-borne pathogens detected?Ch. 41.4 - Why is it advantageous to omit the pre-enrichment...Ch. 41.4 - How is PulseNet used in the surveillance of...Ch. 41.4 - How are most food-borne pathogens detected?Ch. 41.5 - Can you name at least two features that make these...Ch. 41.5 - What are the major types of milk fermentations?Ch. 41.5 - What are the major types of milk fermentations?Ch. 41.5 - What major steps are used to produce cheese? How...Ch. 41.5 - Prob. 1.4RIACh. 41.5 - Describe and contrast the processes of wine and...Ch. 41.5 - How do champagnes differ from wines?Ch. 41.5 - Describe how distilled spirits such as whiskey are...Ch. 41.5 - What microorganisms are most important in...Ch. 41.6 - What bacterial genera are often included in...Ch. 41.6 - How are probiotics used in agriculture?Ch. 41 - Compare the sell-by date of a package of hot dogs...Ch. 41 - You are going through a salad line in a cafeteria...Ch. 41 - Why were aflatoxins not discovered before the...Ch. 41 - What advantage might the Shiga-like toxin give E....Ch. 41 - Keep a record of what you eat for a day or two....Ch. 41 - During cheese production, LAB convert lactose to...Ch. 41 - Following recent outbreaks of E. coli O157:H7...
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- Please indentify the unknown organismarrow_forward5G JA ATTC 3 3 CTIA A1G5 5 GAAT I I3 3 CTIA AA5 Fig. 5-3: The Eco restriction site (left) would be cleaved at the locations indicated by the arrows. However, a SNP in the position shown in gray (right) would prevent cleavage at this site by EcoRI One of the SNPs in B. rapa is found within the Park14 locus and can be detected by RFLP analysis. The CT polymorphism is found in the intron of the Bra013780 gene found on Chromosome 1. The Park14 allele with the "C" in the SNP has two EcoRI sites and thus is cleaved twice by EcoRI If there is a "T" in that SNP, one of the EcoRI sites is altered, so the Park14 allele with the T in the SNP has only one EcoRI site (Fig. 5-3). Park14 allele with SNP(C) Park14 allele with SNPT) 839 EcoRI 1101 EcoRI 839 EcoRI Fig. 5.4: Schematic restriction maps of the two different Park14 alleles (1316 bp long) of B. rapa. Where on these maps is the CT SNP located? 90 The primers used to amplify the DNA at the Park14 locus (see Fig. 5 and Table 3 of Slankster et…arrow_forwardFrom your previous experiment, you found that this enhancer activates stripe 2 of eve expression. When you sequence this enhancer you find several binding sites for the gap gene, Giant. To test how Giant interacts with eve, you decide to remove all of the Giant binding sites from the eve enhancer. What results do you expect to see with respect to eve expression?arrow_forward
- What experiment could you do to see if the maternal gene, bicoid, is sufficient to form anterior fates?arrow_forwardYou’re curious about the effect that gap genes have on the pair-rule gene, evenskipped (eve), so you isolate and sequence each of the eve enhancers. You’re particularly interested in one of the enhancers, which is just upstream of the eve gene. Describe an experimental technique you would use to find out where this particular eve enhancer is active.arrow_forwardFor short answer questions, write your answers on the line provided. To the right is the mRNA codon table to use as needed throughout the exam. First letter U บบบ U CA UUCPhe UUA UCU Phe UCC UUG Leu CUU UAU. G U UAC TV UGCys UAA Stop UGA Stop A UAG Stop UGG Trp Ser UCA UCG CCU] 0 CUC CUA CCC CAC CAU His CGU CGC Leu Pro CCA CAA Gin CGA Arg CUG CCG CAG CGG AUU ACU AAU T AUC lle A 1 ACC Thr AUA ACA AUG Mot ACG AGG Arg GUU GCU GUC GCC G Val Ala GAC Asp GGU GGC GUA GUG GCA GCG GAA GGA Gly Glu GAGJ GGG AACASH AGU Ser AAA1 AAG Lys GAU AGA CAL CALUCAO CAO G Third letter 1. (+7) Use the table below to answer the questions; use the codon table above to assist you. The promoter sequence of DNA is on the LEFT. You do not need to fill in the entire table. Assume we are in the middle of a gene sequence (no need to find a start codon). DNA 1 DNA 2 mRNA tRNA Polypeptide C Val G C. T A C a. On which strand of DNA is the template strand (DNA 1 or 2)?_ b. On which side of the mRNA is the 5' end (left or…arrow_forward
- 3. (6 pts) Fill in the boxes according to the directions on the right. Structure R-C R-COOH OH R-OH i R-CO-R' R R-PO4 R-CH3 C. 0 R' R-O-P-OH 1 OH H R-C-H R-N' I- H H R-NH₂ \H Name Propertiesarrow_forward4. (6 pts) Use the molecule below to answer these questions and identify the side chains and ends. Please use tidy boxes to indicate parts and write the letter labels within that box. a. How many monomer subunits are shown? b. Box a Polar but non-ionizable side chain and label P c. Box a Basic Polar side chain and label BP d. Box the carboxyl group at the end of the polypeptide and label with letter C (C-terminus) H H OHHO H H 0 HHO H-N-CC-N-C-C N-C-C-N-GC-OH I H-C-H CH2 CH2 CH2 H3C-C+H CH2 CH2 OH CH CH₂ C=O OH CH2 NH2arrow_forwardplease answer (A,B,C,D,E) questions with the asnwer choice provided below. thank you!arrow_forward
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