To determine The exit temperature of refrigerant 134a from the nozzle, in °F. Explanation Write the energy rate balance equation. 0 = Q ˙ cv − W ˙ cv + m ˙ [ ( h 1 − h 2 ) + ( V 1 2 − V 2 2 ) 2 + g ( z 1 − z 2 ) ] (I) Here, the rate of heat transfer is Q ˙ cv , rate of work transfer is W ˙ cv , rate of mass flow is m ˙ , the enthalpy is h , velocity is V , gravitational acceleration is g , the elevation is z and the suffixes cv, 1 and 2 indicates control volume, initial and final state of the system respectively. Here, the refrigerant operates in steady state. The inlet, exit of the nozzle is at same elevation and the nozzle is well insulated. Hence, neglect the potential energy i.e. g ( z 1 − z 2 ) = 0 , heat transfer i.e. Q ˙ cv = 0 and the work done i.e. W ˙ cv = 0 . Then the Equation (I) becomes as follows. ( h 1 − h 2 ) + ( V 1 2 − V 2 2 ) 2 = 0 h 2 = h 1 + V 1 2 2 − V 2 2 2 (II) Write the formula to find the quality of the refrigerant at exit. x = h 2 − h f 2 h fg 2 (III) At inlet: Refer Table A-12E, “Properties of Superheated Refrigerant 134a Vapor”. The enthalpy ( h 1 ) of the refrigerant 134a corresponding to the pressure of 200 lbf/in . 2 and the temperature of 220 ° F is 144.15 Btu/lb

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ISBN: 9781119391630

Author: MORAN

Publisher: WILEY

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Chapter 4.12, Problem 32P

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The exit temperature of refrigerant 134a from the nozzle, in °F.

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Chapter 4.12, Problem 31P

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