Explanation Given : h ( t ) = t e − t on [ 0 , 2 ] The given function, h ( t ) = t e − t Now find derivative of h ( t ) h ' ( t ) = e − t − t e − t For critical point, h ' ( t ) = 0 e − t ( 1 − t ) = 0 t = 1 Critical points, t = 1 Now check double derivative for maximum and minimum

6th Edition

ISBN: 9781465208880

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 4.1, Problem 9PS

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To find: The critical numbers of a function, h(t)=te−t on [0,2] and yields a minimum, maximum or neither.

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Chapter 4.1, Problem 8PS

Chapter 4.1, Problem 10PS

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Chapter 4 Solutions

Calculus

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The critical numbers of a function, h ( t ) = t e − t on [ 0 , 2 ] and yields a minimum, maximum or neither.

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To find: The critical numbers of a function, h(t)=te−t on [0,2] and yields a minimum, maximum or neither.

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Chapter 4 Solutions