Explanation Given : g ( x ) = x 2 − 1 x 2 + 1 on [ − 1 , 1 ] The given function, g ( x ) = x 2 − 1 x 2 + 1 Differentiate g ( x ) to find the critical point g ' ( x ) = 4 x ( x 2 + 1 ) 2 For critical point,

6th Edition

ISBN: 9781465208880

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 4.1, Problem 31PS

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To find: The smallest value of g(x)=x2−1x2+1 on [−1,1]

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Chapter 4.1, Problem 30PS

Chapter 4.1, Problem 32PS

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Chapter 4 Solutions

Calculus

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The smallest value of g ( x ) = x 2 − 1 x 2 + 1 on [ − 1 , 1 ]

Solution Summary: The author explains that the smallest value of function on given interval is -1.

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To find: The smallest value of g(x)=x2−1x2+1 on [−1,1]

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Chapter 4 Solutions