Chapter 4.1, Problem 29PPS

To determine

To find: The given element in the matrix.

Answer to Problem 29PPS

The element for matrix is $x^2+4$ .

Explanation of Solution

Given information:

The matrix is $A=\left[\begin{array}{cc}{x}^2+4& y+6\\ x-y& 2-y\end{array}\right],B=\left[\begin{array}{ccc}0& x& -2y\\ 5x& 3y& -4x\\ -y& 0& 0\end{array}\right]$ and the element is $a_{11}$ .

Calculation:

Consider the matrix.

  $A=\left[\begin{array}{cc}{x}^2+4& y+6\\ x-y& 2-y\end{array}\right],B=\left[\begin{array}{ccc}0& x& -2y\\ 5x& 3y& -4x\\ -y& 0& 0\end{array}\right]$

The element $a_{11}$ is the element of matrix A of first row and first column.

Thus, the element for matrix is $x^2+4$ .