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Concept explainers
To describe: the end behavior of the graph of given polynomial function.
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Answer to Problem 17E
Explanation of Solution
Given information:
A function is given as
Concept used:
A polynomial function is of the form
Terms of a polynomial function should be arranged in descending order according to its degree to express it in a standard form and degree of each term should be a positive integer or whole number. The coefficients should be real numbers.
Leading coefficient of a polynomial function is the coefficient of the leading term.
Degree of the polynomial is the degree of leading term or the height degree in the polynomial function.
For the polynomial
The end behavior can describe the graph of a polynomial function as
The end behavior of a polynomial function can be determined by the leading coefficient and the degree of the polynomial.
If degree is even and leading coefficient is negative.
If degree is odd and leading coefficient is negative.
If degree is odd and leading coefficient is positive.
If degree is even and leading coefficient is positive.
Calculation:
Consider the given function.
Now, degree of each term is a whole number and all coefficients are real.
So, the function is polynomial function.
Now, degree of the polynomial function is 4.
Leading term is
So, leading coefficient will be
Degree is even and leading coefficient is negative.
So,
Hence, the end behavior is
Chapter 4 Solutions
Big Ideas Math A Bridge To Success Algebra 2: Student Edition 2015
- The only problems I need help with ae the last 8 ones, Thanksarrow_forwardGraph without using the calculator y-1 = | x+4 |arrow_forward9:43 AS く Akbar © Printed in the United States 15) Scale: 1 cmal unit on both axes .ill 64% The graph above shows a straight line QT intersecting the y-axis at T. i State the co-ordinates of T. ii Calculate the gradient of QT 16) iii Determine the equation of QT. A (-1, 9) ||| i L Г (5 marks)arrow_forward
- Pls help.arrow_forwardSolve the system of equation for y using Cramer's rule. Hint: The determinant of the coefficient matrix is -23. - 5x + y − z = −7 2x-y-2z = 6 3x+2z-7arrow_forwarderic pez Xte in z= Therefore, we have (x, y, z)=(3.0000, 83.6.1 Exercise Gauss-Seidel iteration with Start with (x, y, z) = (0, 0, 0). Use the convergent Jacobi i Tol=10 to solve the following systems: 1. 5x-y+z = 10 2x-8y-z=11 -x+y+4z=3 iteration (x Assi 2 Assi 3. 4. x-5y-z=-8 4x-y- z=13 2x - y-6z=-2 4x y + z = 7 4x-8y + z = -21 -2x+ y +5z = 15 4x + y - z=13 2x - y-6z=-2 x-5y- z=-8 realme Shot on realme C30 2025.01.31 22:35 farrow_forward
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