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Chapter 40, Problem 29P
To determine

To show that the equation 40.32 is the solution 40.30 with energy E=12ω.

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1.62 On a training flight, a Figure P1.62 student pilot flies from Lincoln, Nebraska, to Clarinda, Iowa, next to St. Joseph, Missouri, and then to Manhattan, Kansas (Fig. P1.62). The directions are shown relative to north: 0° is north, 90° is east, 180° is south, and 270° is west. Use the method of components to find (a) the distance she has to fly from Manhattan to get back to Lincoln, and (b) the direction (relative to north) she must fly to get there. Illustrate your solutions with a vector diagram. IOWA 147 km Lincoln 85° Clarinda 106 km 167° St. Joseph NEBRASKA Manhattan 166 km 235° S KANSAS MISSOURI
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