Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Chapter 40, Problem 12RQ
To determine
The example of intermediate workholder concept.
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A 15 cm-OD pipe is buried with its centerline 1.25 m below the surface of the ground
[k of soil is 0.35 W/(m K)]. An oil having a density of 800 kg/m³ and a specific heat of 2.1 kJ/(kg
K) flows in the pipe at 5.6 L/s. Assuming a ground surface temperature of 5°C and a pipe wall
temperature of 95°C, estimate the length of pipe in which the oil temperature decreases by
5.5°C.
+
Tε = 5ºC
Z= 1.25 m
D= 15 cm
7p=95°C
Find the solution of the following Differential Equations
1) 4y+y=0,
y(0)=2,
y'(0) = 0.
2) y+y=0,
y(0) = A,
y'(0) = B.
3) "+2y'-8y=0,
y(0)=1,
y'(0)=8.
4) y"-2y-3y=0,
y(0)=1,
y'(0)=7.
5) y"-ky' =0,
y(0)=2,
y'(0) =k.
6) y+ky'-2k2y=0,
y(0)=2,
y'(0) = 2k.
7) y'+4y=0,
y(0)=2.8
y+y-17sin(21)
y(0)=-1.
9) y-y'-6y=0,
y(0)=6.
y'(0)=13.
10) y-y=0,
11) y"-4y+4y=0,
y(0)=4,
y'(0) = 0.
y(0) = 2.1,
y'(0)=3.9
12) y+2y+2y=0,
y(0)=1,
y'(0)=-3.
13)
"+7y+12y=21e",
y(0)=3.5,
y'(0)=-10.
14) "+9y=10e",
y(0)=0.
y'(0) = 0.
15) y+3y+2.25y=91³ +64.
y(0)=1,
y'(0) = 31.5
16) "-6y+5y= 29 cos(21),
y(0)=3.2,
y'(0) = 6.2
17) y+2y+2y=0,
y(0)=0,
y'(0)=1.
18) y+2y+17y=0,
y(0)=0,
y'(0)=12.
19) y-4y+5y=0,
y(0)-1,
y'(0) 2.
20) 9y-6y+y=0.
y(0)=3,
y'(0)=1.
21) -2y+10y=0,
y(0)=3,
y'(0)=3.
22) 4y-4y+37y=0,
(0) 3.
y(0) 1.5
23) 4y-8y+5y=0,
(0)-0,
y(0) 1.
24) y+y+1.25y=0,
y(0) 1.
y'(0) -0.5
25) y+y=2 cos(1).
y(0) 2.
y'(0) = 0.
26) -4y+3y=0,
(0)-3,
y'(0) = 7.
27) y+2y+y=e",
y(0)-0.
y'(0) = 0.
29)
28) y+2y-3y-10sinh(2),…
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Chapter 40 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 40 - What are the two primary functions of a...Ch. 40 - Prob. 2RQCh. 40 - An early treatise defined a jig as a device that...Ch. 40 - Does an ordinary vise qualify as a fixture? Why or...Ch. 40 - What basic criteria should be considered in...Ch. 40 - In any part drawing, what are the critical...Ch. 40 - What difficulties can result from not keeping...Ch. 40 - Prob. 8RQCh. 40 - Which of the basic design principles relating to...Ch. 40 - What are the two reasons for not having drill...
Ch. 40 - Why does the use of down milling often make it...Ch. 40 - Prob. 12RQCh. 40 - A large assembly jig for an airplane-wing...Ch. 40 - Explain why the use of a given fixture may not be...Ch. 40 - Prob. 15RQCh. 40 - In the clamps shown in Figure 40.20, what is the...Ch. 40 - What are other common types of clamp?Ch. 40 - What is the purpose of dimensioning the...Ch. 40 - Prob. 19RQCh. 40 - In Figure 49.9. why arent there three points put...Ch. 40 - Which set of locators in Figure 49.9 establishes...Ch. 40 - What are the four stages of the SMED methodology...Ch. 40 - Prob. 23RQCh. 40 - How could the intermediate jig concept be used in...Ch. 40 - Develop a sequence of operations to produce the...Ch. 40 - Suppose in the sample problem at the end of this...Ch. 40 - Notice that the holes in the part in Figure 49.9...Ch. 40 - Prob. 6PCh. 40 - A part has two holes located for drilling by...
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