Database Systems: Design, Implementation, Management, Loose-leaf Version
12th Edition
ISBN: 9781305866799
Author: Coronel, Carlos; Morris, Steven
Publisher: Course Technology
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Question
Chapter 4, Problem 7RQ
a)
Program Plan Intro
Graphical representation of ERM (Entity Relationship Model) entity component:
Crow’s Foot entity box for “Student”
b)
Program Plan Intro
Graphical representation of ERM cardinality component:
The following table illustrates the different connectivity and participation combinations which are maintained by the Crow’s Foot notation:
Crow’s Foot cardinality notation
| Notation | Cardinality | Description |
 |
(0,N) | Zero or more instances |
 |
(1,N) | One or more instances |
 |
(1,1) | One instance |
 |
(0,1) | Zero or one instance |
c)
Program Plan Intro
Graphical representation of ERM entity component:
Crow’s Foot weak relationship symbol
d)
Program Plan Intro
Graphical representation of ERM entity component:
Crow’s Foot strong relationship symbol
Expert Solution & Answer
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Students have asked these similar questions
1. Create a Book record that implements the Comparable interface, comparing the
Book objects by year
- title: String
>
- author: String
- year: int
Book
+ compareTo(other Book: Book): int
+ toString(): String
Submit your source code on Canvas (Copy
your code to text box or upload.java file)
>
Comparable
2. Create a main method in Book record.
1) In the main method, create an array of 2 objects of Book with your choice of
title, author, and year.
2) Sort the array by year
3) Print the object. Override the toString in Book to match the example output:
@Javadoc Declaration Console X Properties
Book [Java Application] /Users/kuan/.p2/pool/plugins/org.eclipse.justj.openjdk.hotspo
[Book: year=1901, Book: year=2010]
Q5-The efficiency of a 200 KVA, single phase transformer is 98% when operating at full load 0.8
lagging p.f. the iron losses in the transformer is 2000 watt. Calculate the i) Full load copper losses ii)
half load copper losses and efficiency at half load. Ans: 1265.306 watt, 97.186%
2. Consider the following pseudocode for partition:
function partition (A,L,R)
pivotkey = A [R]
t = L
for i
L to R-1 inclusive:
if A[i] A[i]
t = t + 1
end if
end for
A [t] A[R]
return t
end function
Suppose we call partition (A,0,5) on A=[10,1,9,2,8,5]. Show the state of the list at the
indicated instances.
Initial A
After i=0 ends
After 1 ends
After i 2 ends
After i = 3 ends
After i = 4 ends
After final swap
10 19 285
[12 pts]
Chapter 4 Solutions
Database Systems: Design, Implementation, Management, Loose-leaf Version
Ch. 4 - Prob. 1RQCh. 4 - What is a strong (or identifying) relationship,...Ch. 4 - Prob. 4RQCh. 4 - Suppose you are working within the framework of...Ch. 4 - Prob. 6RQCh. 4 - Prob. 7RQCh. 4 - Discuss the difference between a composite key and...Ch. 4 - What two courses of action are available to a...Ch. 4 - Prob. 11RQCh. 4 - Discuss two ways in which the 1:M relationship...
Ch. 4 - Prob. 13RQCh. 4 - Prob. 14RQCh. 4 - Briefly, but precisely, explain the difference...Ch. 4 - What are multivalued attributes, and how can they...Ch. 4 - Prob. 17RQCh. 4 - Prob. 18RQCh. 4 - What two attributes must be contained in the...Ch. 4 - Describe precisely the composition of the...Ch. 4 - Prob. 21RQCh. 4 - Prob. 1PCh. 4 - Create a complete ERD in Crows Foot notation that...Ch. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10PCh. 4 - Prob. 11C
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