The vector position of a particle varies in time according to the expression r → = 3.00 i ^ − 6.00 t 2 j ^ , where r → is in meters and t is in seconds. (a) Find an expression for the velocity of the particle as a function of time. (b) Determine the acceleration of the particle as a function of time. (c) Calculate the particle’s position and velocity at t = 1.00 s.
The vector position of a particle varies in time according to the expression r → = 3.00 i ^ − 6.00 t 2 j ^ , where r → is in meters and t is in seconds. (a) Find an expression for the velocity of the particle as a function of time. (b) Determine the acceleration of the particle as a function of time. (c) Calculate the particle’s position and velocity at t = 1.00 s.
Solution Summary: The author explains the expression for the velocity as a function of time, and the formula for calculating acceleration.
The vector position of a particle varies in time according to the expression
r
→
=
3.00
i
^
−
6.00
t
2
j
^
, where
r
→
is in meters and t is in seconds. (a) Find an expression for the velocity of the particle as a function of time. (b) Determine the acceleration of the particle as a function of time. (c) Calculate the particle’s position and velocity at t = 1.00 s.
Three point-like charges in the attached image are placed at the corners of an equilateral triangle as shown in the figure. Each side of the triangle has a length of 38.0 cm, and the point (C) is located half way between q1 and q3 along the side. Find the magnitude of the electric field at point (C). Let q1 = −2.80 µC, q2 = −3.40 µC, and q3 = −4.50 µC. Thank you.
Three point-like charges are placed as shown in the attach image, where r1 = r2 = 44.0 cm. Find the magnitude of the electric force exerted on the charge q3. Let q1 = -1.90 uC, q2 = -2.60 uC, and q3 = +3.60 uC. Thank you.
The drawing attached shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface (1) has an area of 1.90 m², while Surface (2) has an area of 3.90 m². The electric field in magnitude of 215 N/C. Find the magnitude of the electric flux through surface (1 and 2 combined) if the angle theta made between the electric field with surface (2) is 30.0 degrees. Thank you.
Chapter 4 Solutions
Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)
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